Help with Conics: Change General Form to Standard Form

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The discussion focuses on converting the general form of a conic equation into standard form, specifically addressing the equation 2x^2 + y^2 + 12x – 2y + 15=0. The main confusion arises from completing the square and factoring correctly. Participants emphasize the importance of factoring out the coefficient of x^2 before completing the square, which leads to the correct transformation of the equation. The final standard form is derived as (x+3)^2/2 + (y-1)^2/4 = 1, highlighting the necessity of proper steps in the process. Overall, the thread provides clarity on the method for changing conic forms effectively.
ms. confused
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Ok I seem to be having problems with changing the general form of a conic to standard form. I'm mainly confused with how to factor, since I haven't done it in a while, as well as how to go about completing the square.

Here's one of my problems:

2x^2 + y^2 + 12x – 2y + 15=0

I rearranged it to look like: 2x^2 + 12x + y^2 – 2y + 15=0

Then I "supposedly" completed the square:

(2x^2 + 12x +36) + (y^2 – 2y +1)= 22

Factoring is where I got stuck: 2(x^2 + 6x +18) + (y-1)^2= 22

I don't know what to do with what I got and the answer is supposed to be:

(x+3)^2 / 2 + (y-1)^2 / 4 = 1
 
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(2x^2 + 12x +36)

Your problem is that this isn't a square! (Though, x^2 + 12x + 36 is) Your problem is you need to factor out the two first, so that the coefficient on x^2 is a 1.
 
I did that and I got 2(x^2 + 6x +18).
 
1. 2x^2 + 12x + 18 which is equivalent to 2(x+3)(x+3) + y^2 - 2y + 1 which is equivalnt to (y-1)(y-1) = -15 + 18 +1
2. Your equation is 2(x+3)^2 + (y-1)^2 = 4
3. Divide each side by 4. Now you have:
2(x+3)^2/4 + (y-1)^2/4 = 4/4
4. Now, your final product is:
(x+3)^2/2 + (y-1)^2/4 = 1

Is that the needed answer?
 
You need to factor before you figure out the constant term. You picked 36, then factored, which is the wrong way around.
 
How did you get 2x^2 + 12x + 18? I got 2x^2 + 12x + 36.
 
All you know is 2x^2 + 12x + ?.

Factor out the two to make it easy.

Now you have 2(x^2 +6x + ?)

Then you can fill in the square by making it 2(x^2 + 6x + 9) or 2(x+3)^2
 
This should give you 2x^2 + 12x + 18.

I hope I'm doing this right...
 
If you know the answer,then u can cheat:
1.Make in the initial quadratic form the 2 substitutions
x\rightarrow u-3
v\rightarrow v+1

2.Show that the new quadratic form is
\frac{u^{2}}{2}+\frac{v^{2}}{4}=1

3.Reverse the substitution and find the answer.

Daniel.
 
  • #10
Oh I see! Thanks for the help guys!
 

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