Help with deriving transfer function of a second order control system

Click For Summary
SUMMARY

The discussion focuses on deriving the overall transfer function of a second-order control system based on a provided block diagram. The transfer function is represented as Gc(s) = Kp (1 + (1/Ti(s))). Participants emphasize the need to isolate H terms to simplify the equation and derive expressions for the natural frequency and damping ratio. The relationship between the integral time (Ti) and the system parameters is also highlighted, indicating its dependency on the natural frequency and damping ratio.

PREREQUISITES
  • Understanding of control systems and transfer functions
  • Familiarity with second-order system dynamics
  • Knowledge of block diagram representation in control theory
  • Proficiency in manipulating algebraic equations in the context of control systems
NEXT STEPS
  • Study the derivation of transfer functions for second-order systems
  • Learn about natural frequency and damping ratio calculations
  • Explore the implications of integral time (Ti) in control systems
  • Review block diagram reduction techniques in control theory
USEFUL FOR

Students and professionals in control engineering, particularly those working on system dynamics and transfer function analysis in second-order systems.

mcds
Messages
1
Reaction score
0

Homework Statement



Please see attachment for block diagram of the system.

Starting with the block diagram given in Figure 2 derive an expression for the overall transfer
function of the system, where Gc(s) is in the form given by Eq. (1). Show that the system is a
Second Order system. Derive expressions for the natural frequency and damping ratio of the
system in terms of the system parameters given in the Theory section of DTC lecture notes. Show
the dependency of TI on the natural frequency and damping ratio.
Starting with the block diagram given in Figure 2 derive an expression for the error voltage VE.

Homework Equations



Equation 1 ------> Gc(s) = Kp (1+(1/Ti(s)))

The Attempt at a Solution



HRK – HK = Ve
[(Gc x Ve) + (vRef) x (Km)] x (R/1 + ARs) = H
H ((1 + ARs)/R) = [(Gc x Ve) + (vRef) x (Km)]
H ((1 + ARs)/ Km x R) = [(Gc x Ve) + (vRef) ]
H ((1 + ARs)/ Km x R) - (vRef) = [(Gc x Ve)]
[H ((1 + ARs)/ Km x R) - (vRef)] x (1/Ve) = Gc
[H ((1 + ARs)) - (vRef) (Km x R)] x (1/Ve) = Gc (Km x R)
[H ((1 + ARs)) - (vRef) (Km x R)/Ve) = Gc (Km x R)
[H ((1 + ARs)) - (vRef) (Km x R)/(HRK – HK)) = Gc (Km x R)

I am not sure how to proceed from this point onwards and would be very grateful for help/pointers in the right direction. I am told that I need to get all the H terms on one side of the equation if this helps.
 

Attachments

  • blockdiargam.JPG
    blockdiargam.JPG
    12.8 KB · Views: 575
Physics news on Phys.org
mcds said:

Homework Statement



Please see attachment for block diagram of the system.

Starting with the block diagram given in Figure 2 derive an expression for the overall transfer
function of the system, where Gc(s) is in the form given by Eq. (1). Show that the system is a
Second Order system. Derive expressions for the natural frequency and damping ratio of the
system in terms of the system parameters given in the Theory section of DTC lecture notes. Show
the dependency of TI on the natural frequency and damping ratio.
Starting with the block diagram given in Figure 2 derive an expression for the error voltage VE.

Homework Equations



Equation 1 ------> Gc(s) = Kp (1+(1/Ti(s)))

The Attempt at a Solution



HRK – HK = Ve
[(Gc x Ve) + (vRef) x (Km)] x (R/1 + ARs) = H
H ((1 + ARs)/R) = [(Gc x Ve) + (vRef) x (Km)]
H ((1 + ARs)/ Km x R) = [(Gc x Ve) + (vRef) ]
H ((1 + ARs)/ Km x R) - (vRef) = [(Gc x Ve)]
[H ((1 + ARs)/ Km x R) - (vRef)] x (1/Ve) = Gc
[H ((1 + ARs)) - (vRef) (Km x R)] x (1/Ve) = Gc (Km x R)
[H ((1 + ARs)) - (vRef) (Km x R)/Ve) = Gc (Km x R)
[H ((1 + ARs)) - (vRef) (Km x R)/(HRK – HK)) = Gc (Km x R)

I am not sure how to proceed from this point onwards and would be very grateful for help/pointers in the right direction. I am told that I need to get all the H terms on one side of the equation if this helps.

You have two input signals: HRK and Vref. You can have a transfer function only relative to one of them. To obtain the TF relative to HRK, make Vref = 0. To obtain the TF relative to Vref, make HRK = 0.
I have not followed your development, but I believe it is wrong, because if you make Vref = 0, HRK disappears from the equation.
 

Similar threads

Replies
24
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
3K
  • · Replies 12 ·
Replies
12
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 13 ·
Replies
13
Views
5K