Help with differential understanding

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Homework Help Overview

The discussion revolves around the dynamics of a simple pendulum, specifically analyzing the time taken to traverse different angular segments from the vertical position. The original poster is exploring the relationship between angular displacement and speed, as well as the application of differentiation in this context.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the derivation of a velocity expression related to angular displacement and questions the steps involved in applying differentiation to this expression. Some participants discuss the chain rule of differentiation in relation to the problem.

Discussion Status

Participants are engaging with the mathematical aspects of the problem, with some providing insights into differentiation. The original poster expresses a newfound understanding of the physical implications of the mathematics involved, indicating a productive direction in the discussion.

Contextual Notes

There appears to be a focus on the application of conservation laws and the mathematical tools necessary for analyzing motion in the context of a pendulum. The original poster's understanding of differentiation is also a point of discussion.

Bestfrog

Homework Statement


A simple pendulum in quiet is released from the horizontal (##\theta=0##) (##\theta=90## for the vertical). Will the pendulum cover in the smaller time the arch from ##\theta=0## to ##\theta=30## or from ##\theta=30## to ##\theta=90##?

The Attempt at a Solution


I would like to know one thing: by the conservation on law, the speed in function of ##\theta## is ##v=\sqrt{2glsin\theta}##. Then I found a solution that says: "taking the differential I get ##dv= \sqrt{2gl} \frac{cos\theta}{2 \sqrt{sin\theta}} d\theta##. How can this passage is possible? I don't understand what happen
 
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Suppose you are given:

##f(u)=k\left(\sin(u)\right)^{\frac{1}{2}}##

Using the power and chain rules, what do you get for:

##\dfrac{df}{du}=?##
 
Bestfrog said:
taking the differential I get dv=√2glcosθ2√sinθdθdv=2glcosθ2sinθdθdv= \sqrt{2gl} \frac{cos\theta}{2 \sqrt{sin\theta}} d\theta. How can this passage is possible? I don't understand what happen
It is based on the chain rule of differentiation. Have you studied differentiation?
 
Yes I know. Now I understand the physical meaning
 

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