- #1

Bling Fizikst

- 35

- 5

- Homework Statement
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- Relevant Equations
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Since the ball will follow a parabolic trajectory , i threw it into the coordinate plane with particle starting from the origin .

$$y= kx^2$$ Differentiating wrt ##t## : $$ gt=2ku^2 t\implies u=\sqrt{\frac{g}{2k}}$$ where $$k=\frac{\sin\theta}{R\cos^2\theta}$$ Now , final speed when it reached the bottom is $$\sqrt{u^2+2gh}$$ but I am stuck here on how to find ##h## in terms of ##\theta## in order to minimise the expression .