Help with differential understanding

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Bestfrog

Homework Statement


A simple pendulum in quiet is released from the horizontal (##\theta=0##) (##\theta=90## for the vertical). Will the pendulum cover in the smaller time the arch from ##\theta=0## to ##\theta=30## or from ##\theta=30## to ##\theta=90##?

The Attempt at a Solution


I would like to know one thing: by the conservation on law, the speed in function of ##\theta## is ##v=\sqrt{2glsin\theta}##. Then I found a solution that says: "taking the differential I get ##dv= \sqrt{2gl} \frac{cos\theta}{2 \sqrt{sin\theta}} d\theta##. How can this passage is possible? I don't understand what happen
 
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Suppose you are given:

##f(u)=k\left(\sin(u)\right)^{\frac{1}{2}}##

Using the power and chain rules, what do you get for:

##\dfrac{df}{du}=?##
 
Bestfrog said:
taking the differential I get dv=√2glcosθ2√sinθdθdv=2glcosθ2sinθdθdv= \sqrt{2gl} \frac{cos\theta}{2 \sqrt{sin\theta}} d\theta. How can this passage is possible? I don't understand what happen
It is based on the chain rule of differentiation. Have you studied differentiation?
 
Yes I know. Now I understand the physical meaning