Help with electrostatics problem (spherical shell charge distribution)

Click For Summary
The discussion centers on a problem involving a spherical shell with a charge density of ρ=a+br, where the professor claims the solution in a referenced book is incorrect, particularly for finding electric potentials and energy density for r < R1. Participants express confusion over the integration process and the assertion that the electric field remains constant across regions, which they argue is inaccurate. There is a consensus that the charge is only present between the inner radius R1 and outer radius R2, making the problem's context crucial. Additionally, the notation used in the solution is criticized for being misleading, as it suggests a dependence on r when it is actually constant. Overall, the thread highlights significant misunderstandings regarding the problem's solution and the implications of the charge distribution.
sroot
Messages
2
Reaction score
0
Homework Statement
A static electric charge is distributed in a spherical shell of inner radius R1 and outer radius R2. The electric charge density is given by ρ=a+br, where r is the distance from the centre, and zero everywhere else.
(i) Find an expression for the electric field everywhere in terms of r.
(ii) Find expressions for the electric potentials and energy density for r < R1. Take the potential to be zero at r→∞.
Relevant Equations
ρ=a+br
Physics news on Phys.org
sroot said:
Homework Statement:: A static electric charge is distributed in a spherical shell of inner radius R1 and outer radius R2. The electric charge density is given by ρ=a+br, where r is the distance from the centre, and zero everywhere else.
(i) Find an expression for the electric field everywhere in terms of r.
(ii) Find expressions for the electric potentials and energy density for r < R1. Take the potential to be zero at r→∞.
Relevant Equations:: ρ=a+br

According to my professor, the solution in this book (pages 20-21) for item (ii) is wrong: https://www.u-cursos.cl/usuario/754...roblems_and_Solutions_on_Electromagnetism.pdf
Welcome to PF.

Can you please just take screenshots of the pages that you want to discuss? Asking us to download the whole book PDF file is a bit too much. And please explain what is confusing you about the solution. Thank you.
 
berkeman said:
Welcome to PF.

Can you please just take screenshots of the pages that you want to discuss? Asking us to download the whole book PDF file is a bit too much. And please explain what is confusing you about the solution. Thank you.

This is the solution for item (b). According to the professor, the integral is completely off. I can't understand why.
Screenshot_2020-12-03 Problems_and_Solutions_on_Electromagnetism pdf.png
 
Did you carry out the integrations? What did you get for the results of the individual integrals?
 
It looks like the solution asserts that the electric field is the same in all regions by showing it factored out of the integrals. That is simply not true. I started doing the integrals but I quit before I got to the bottom line when it became obvious that my expression would not simplify to the answer shown above.

I interpreted "The electric charge density is given by ρ=a+br, where r is the distance from the centre, and zero everywhere else" to mean that there is charge only in the region ##R_1\leq r \leq R_2## "everywhere else" being outside this region. Otherwise why bother mentioning a shell?

Also, it is misleading (but not an error) to write the left hand side as ##\varphi (r)## when it is actually independent of ##r##.
 
Last edited:
  • Like
Likes berkeman
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
4
Views
2K
Replies
9
Views
2K
Replies
12
Views
2K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
21
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
12
Views
3K