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- Thread starter dam
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Mark44

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"Explicit" is not a verb, so I don't understand what "expliciting" is supposed to mean. The fact that you have a product on the left side is useful only if the right side happens to be zero. For example, if (x + 2)(y + 3) = 0, then I can say something about x and y, but if (x + 2)(y + 3) = 1, then I really can't say anything useful about x and y.Hi, can anybody help me with this differential equation? (px-y)(py-x)=a^2*p, where p=y'. I tried to solve it by expliciting the two solutions for y as functions of p and x

Do you mean "differentiate"? If so, I'm not following what you're trying to do. Or do you mean "integrate"?dam said:and then derive

If you expand the product on the left side of your equation above, you get a quadratic in y'. You can use the Quadratic formula to get two first-order differential equations. I haven't gone any further than this, as what you get is pretty messy.dam said:, in order to obtain two first order differential equations in p but these are impossible to solve. I also tried to find the singular solution of the equation but it turned out that there is not a singular solution! I really don't know what to do, can anybody help me? Thank you in advance :)

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Svein

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If you multiply out, you get a 2. degree equation in y'. Solve for y' and then solve the resulting two differential equations.

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Mark44

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That's pretty much what I said in post #2.If you multiply out, you get a 2. degree equation in y'. Solve for y' and then solve the resulting two differential equations.

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Svein

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Sorry, I got sidetracked by the rest of your post (and the reply from the OP).That's pretty much what I said in post #2.

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