Help with Frames Physics: Determining Reactions at A and E for Two 10-Inch Pipes

  • Thread starter Thread starter jaredmt
  • Start date Start date
  • Tags Tags
    Frames Physics
Click For Summary
SUMMARY

This discussion focuses on determining the reactions at supports A and E for two 10-inch diameter pipes, each weighing 22 lb/ft and supported every 10 feet. The total weight of both pipes is calculated to be 220 lb, with each pipe contributing 110 lb. The solution involves applying the principles of static equilibrium by setting the moments around the supports to zero and analyzing the forces acting on each pipe, including gravity and the reactions at the supports.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of moment calculations in physics
  • Familiarity with forces acting on structures
  • Basic understanding of pipe weight distribution
NEXT STEPS
  • Study the principles of static equilibrium in mechanical systems
  • Learn about moment calculations and their applications in engineering
  • Explore the effects of frictionless surfaces on structural analysis
  • Investigate the weight distribution of cylindrical objects in support systems
USEFUL FOR

Engineering students, mechanical engineers, and anyone involved in structural analysis and design of support systems for pipes.

jaredmt
Messages
120
Reaction score
0

Homework Statement


Two 10-inch diameter pipes (pipe 1 and pipe2) are supported every 10ft by a small frame like the one shown. Knowing that the combined weight per unit length of each pipe and its contents is 22 lb/ft and assuming frictionless surfaces, determine the components of the reactions at A and E.

attachment.php?attachmentid=16677&d=1228194586.jpg

Homework Equations


The Attempt at a Solution


first id like to make sure I am doing the weight of the pipe correctly:

Wboth = (22 lb/ft)(10ft) = 220lb. W1 = W2 = 110lbs

now that its all typed out i think i know what to do, but just correct me if I am wrong. i can get the vertical forces of A and E by finding the moment of the entire frame and setting it to 0. (the only forces involved are the weight of both pipes. A and E counter act it to make a moment of 0)
Then i can find all forces acting on Pipe 2, which is pipe 1, the pole and gravity pulling it down.
Then i find the forces acting on Pipe 1 which is pipe 2, both poles, and gravity.
Then i find the moment about the brown dot for each pole individually to find the horrizontal forces of A and Eedit: and also i believe the horizontal distance from the brown dot to where pipe 2 makes contact with the pole is 1.5rsin(theta)
the horizontal distance of pipe 1 is just rsin(theta).
 

Attachments

  • fig p6.92a.JPG
    fig p6.92a.JPG
    10.7 KB · Views: 461
Last edited:
Physics news on Phys.org


ok nevermind, i just went through this problem and got the same answer they had in the book. its kind of annoying, that's like the 3rd problem this week where i figured it out as i was finished typing everything up and drawing the picture lol
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
5K
  • · Replies 42 ·
2
Replies
42
Views
4K
Replies
4
Views
3K
Replies
7
Views
3K
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
5K
Replies
1
Views
8K