Help with inverse function problem

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Homework Help Overview

The problem involves finding the inverse of the function f(x) = x + cos(x) at the point where the output is 1. The original poster expresses uncertainty about how to isolate y in the equation derived from the function.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the feasibility of expressing the inverse function in terms of elementary functions and explore the definition of inverse functions. There is a focus on identifying the x value that results in f(x) = 1, with some questioning the ability to solve for y explicitly.

Discussion Status

Some participants have provided insights regarding the nature of the function and its behavior, suggesting that there may be a unique solution for f^-1(1). However, the discussion reflects varying levels of understanding about the implications of the function's properties.

Contextual Notes

The original poster is new to forum discussions and has requested feedback on their posting style. There is an indication that the function is nondecreasing, which may influence the interpretation of solutions.

crm08
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Homework Statement



If f(x) = x + cos(x), find f-inverse of (1)

Homework Equations



**first time asking a forum question, please inform me of any errors in posting this question

The Attempt at a Solution



(1) y = x + cos(x) => if y = f(x)

(2) x = y + cos(y) => if x = f(y)

(3) ** solve for y? this is where I am stuck, is it possible to completely show work and solve for "y" before plugging in "1"? I tried switching the variables and using the solve command on my ti-89 and it gives the answer:
cos(y) + y = x
 
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I don't think there is anyway of expressing the inverse of that function in terms of elementary function (someone with a more authoritative math background could clarify). However, if we note the definition of an inverse function: f:X -> Y than f^-1:Y -> X we can find a solution for f^-1(1). Hence, to find f^-1(1) all we need find is the x value which produces an f(x) value of 1; therefore, 1 = x + cos(x). Can you solve that?
 
Ok gotcha, x = 0, thanks for the help
 
Yep, so f^-1(1) = 0.
 
There is no other solution to f(x) = 1 because f is nondecreasing everywhere and increasing at 0 (use f' to show this).
 

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