Help With Net Force Formula and Newton's Second Law

In summary, the mass of the system was 2.7kg and the slope of the best fit line (Fn on y-axis and a on x-axis) was 2.5kg. When comparing force, mass, and acceleration, it was found that force was directly proportional to mass and acceleration, both theoretically and experimentally. However, when comparing mass and acceleration, there was some discrepancy between the predicted inverse relationship and the observed increase in both variables. Further analysis of the experimental data, including taking into account measurement accuracy and error bars, is necessary to determine the validity of Newton's Second Law in this case. It is important to note that no experimental evidence can definitively prove a physics law or formula, but only support it within
  • #1
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Homework Statement


1. Compare the mass of the system to the slope. Does your data support Newton's Second Law?

2. Using the words "directly" or "indirectly" briefly explain how force, mass, and acceleration are related to each other, making specific references to the parts of the Fletcher's apparatus used in this lab.

The mass of the system is 2.7kg, while the slope of the best fit line (Fn on y-axis and a on x-axis) is 2.5kg.

Homework Equations


Fnet = ma


The Attempt at a Solution


For 1., I stated that my best fit line was close to the actual mass of the system. However, I don't understand how to explain the second part regarding Newton's Second Law.

2. It was obvious to me that force was directly proportional to force and mass, both theoreticall and experimentally. However, I ran into trouble when I was comparing mass and acceleration. Although they should be inversely proportional from the formula (multiplying and same side of equation), both increase at the same time (although non-linear) from the experimental data.

Thanks.
 
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  • #2
Do you have a graph of F vs a? If so, you must decide whether or not a straight line fits the data points to within the accuracy of the experiment (error bars?) and whether the slope of the line is equal to the mass to within the accuracy of the experiment (would a line of slope m fit most of the error bars?) and the y-intercept is zero (to within ...). Only if all three conditions are met can you say that
y = mx + b --> F = ma
 
  • #3
Delphi51 said:
Do you have a graph of F vs a? If so, you must decide whether or not a straight line fits the data points to within the accuracy of the experiment (error bars?) and whether the slope of the line is equal to the mass to within the accuracy of the experiment (would a line of slope m fit most of the error bars?) and the y-intercept is zero (to within ...). Only if all three conditions are met can you say that
y = mx + b --> F = ma

The line of best fit is a straight line. The equation of the line of best fit, calculated using linear regression, is y = 2.42x + 0.21. The slope from graphing the data is 2.5kg.
 
  • #4
Accuracy of the data? When you measured the force, what measuring device did you use? How accurate is it? How accurately did you record the force? If you have reasonably good equipment, the recording accuracy is a pretty good estimate. For example, if you recorded the force to the nearest tenth of a Newton then plus or minus 0.05 N is a reasonable estimate.

How did you measure acceleration? A typical method is to record dots on tape every tenth of a second and measure the distance between dots to the nearest mm. Assuming that the timing is pretty accurate, the main inaccuracy comes from rounding the distance. For example, if each distance measurement is plus/minus .05 cm then the delta d is twice that - 0.1 cm. Doing v = d/t where t is 0.1 seconds gives you plus or minus 1 cm/s. Delta v is plus/minus 2 cm/s. and acceleration = delta v divided by 0.1 s is plus/minus 20 cm/s.

If you put in vertical error bars for the force error and horizontal error bars for the acceleration error, then you will be able to say whether or not your straight line fits the data points to with their error bars representing the accuracy of measurement.

Bear in mind that you can never "prove" any physics law or formula. The best you can say is that it fits the experimental data to within its measurement accuracy. Some say you try your best to disprove it and if you fail it stays on the books for a more accurate test later.
 

What is the Net Force formula?

The Net Force formula is a mathematical equation that represents the total force acting on an object. It is calculated by adding up all of the individual forces acting on the object and taking into account the direction and magnitude of each force.

What is Newton's Second Law?

Newton's Second Law, also known as the Law of Acceleration, states that the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to its mass. This means that an object with a greater mass will require a larger force to accelerate at the same rate as an object with a smaller mass.

How do I calculate the net force on an object?

To calculate the net force on an object, you must first identify all of the forces acting on the object. Then, use the Net Force formula (Fnet = ∑F) to add up all of the individual forces, taking into account their direction and magnitude. The resulting number is the net force acting on the object.

What units are used for net force and mass in the Net Force formula?

The unit for net force in the Net Force formula is Newtons (N), which is a unit of force in the metric system. The unit for mass is kilograms (kg), which is a unit of mass in the metric system. It is important to use consistent units when calculating net force to ensure accuracy.

How does Newton's Second Law apply to real-life scenarios?

Newton's Second Law is applicable to various real-life scenarios, such as calculating the force required to push a car or the acceleration of a rocket. It also helps explain everyday experiences, such as why it is easier to push a lighter object than a heavier one. Understanding this law can also aid in designing and improving technologies, such as vehicles and sports equipment.

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