Help with point charges and electric fields

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SUMMARY

The discussion focuses on calculating the electric field at the center of a square formed by four point charges, each of magnitude q. Two configurations are analyzed: one with alternating charges (+q, -q, +q, -q) and another with two positive charges at the top corners and two negative charges at the bottom corners. It is established that the second configuration produces a greater electric field magnitude, calculated as -4√2 kq/a², while the first configuration results in a net electric field of zero due to charge cancellation.

PREREQUISITES
  • Understanding of electric fields and point charges
  • Familiarity with Coulomb's Law (E = k * |q| / r²)
  • Basic knowledge of vector addition in physics
  • Concept of symmetry in electric fields
NEXT STEPS
  • Study the derivation of electric fields from point charges using vector components
  • Learn about the principle of superposition in electric fields
  • Explore the effects of charge arrangement on electric field strength
  • Investigate the implications of electric field calculations in real-world applications
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Students in physics, particularly those studying electromagnetism, educators teaching electric fields, and anyone preparing for exams involving electrostatics.

lyndan
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Homework Statement



So the question states: Four point charges, each of magnitude q, are located at the corners of a square with sides of length a. Two of the charges are +q and two are -q. The charges are arranged in one of the following two ways: (1) The charges alternate in sign (+q,-q,+q,-q) as you go around the square; (2) the top two corners of the square have positive charges (+q,+q) and the bottom two corners of the square have negative charges (-q,-q). (a) In which case will the electric field at the center of the square have the greatest magnitude? explain. (b) calculate the electric field at the center of the square for each of these two cases


The Attempt at a Solution



I already figured out that the electric field will have a greater magnitude in the second case, because the point charges in the first square will essentially cancel each other out? I can't figure out how to calculate the electric field at the center...I started using the E=klql/r^2 but I am just having trouble getting the answer...the first answer is zero and the answer to the second on is -4 2^1/2 kq / a^2 but so far I've been unable to get that

any help would be great thank you so much!
 
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lyndan said:
...the first answer is zero and the answer to the second on is -4 2^1/2 kq / a^2 but so far I've been unable to get that

any help would be great thank you so much!

Hi lyndan! :smile:

Show us how far you've got, and then we'll be able to see where the difficulty is. :wink:
 

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