Help with simple secondary school Physics question.

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Homework Help Overview

The discussion revolves around converting units in physics, specifically from meters squared to centimeters cubed, kilometers per hour to meters per second, and meters per second to kilometers per hour. The original poster expresses confusion regarding the requirements of the problems and the concept of standard form or scientific notation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the conversion of units and the interpretation of "standard form." There is a focus on identifying potential typos in the original problem statement and clarifying the meaning of standard form. The original poster shares their attempts at conversion and expresses uncertainty about the steps required.

Discussion Status

Participants have provided insights into unit conversions and the significance of significant figures. Some have pointed out the need for clarity regarding the original problem's wording, while others have offered guidance on how to approach the conversion of specific units. The discussion remains open, with various interpretations being explored.

Contextual Notes

The original poster is new to physics and is working on a secondary school homework assignment. There is mention of potential errors in the problem setup, which may affect the understanding of the tasks at hand.

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Homework Statement


Convert the number below by giving the answer in standard form.

Homework Equations


1) 0.0012m(to the power of 2) = _____ cm(to the power of 3)
2) 12kmh(to the power of -1) = _____ ms(to the power of -1)
3) 12ms(to the power of -1) = _____ kmh(to the power of -1)

My effort of showing that i tried.
1)2)3) i convert the number to cm/ms/kmh first. then change it to standard form, but i still don't get what the question really want, and what is the step required. And the answer look really strange. I've been trying this for the whole afternoon until now.

P/S I saw a lot of complicated question being asked here, but i am new to Physics, and currently stuck at my Physics Chapter 1 homework which is a secondary school standard.
Hope i get a proper formula with answer ASAP. Thanks T_T
 
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Do you have a typo in the first problem? What do you mean by "standard form"?
 
well, typo for grammar is a yes i guess. But not "standard form" i think.

Kay, i'll give you an easier example that i know.
Convert the number below and write the answer in standard form.
(A) 7.2m to cm
So, it's 720cm after converted. And so, the answer in standard form are,
7.2 x 10(to the power of) -2 cm

Yes, if my post confused you, I'm sorry for the inconvenient caused. Because this is what i learned recently, and I'm new to this forum.Edited*
Oh yeah, another name for "Standard Form" is called the "Scientific Notation".
-Standard form is based on powers of base number 10. In standard form, the magnitude or numerical value of physical quantity can be written as:

A x 10 (to the power of) x
 
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OK, that's what I thought you meant by "standard form". The typo I'm referring to are the powers in the first problem. There's no way to convert m2 to cm3.
 
Yes, that's one of the problem that i don't understand too, if you say so, then i guess maybe it's my teacher's mistake for the powers typo.
Thanks for pointing that out.

But do you have any ideas on how to solve the 2nd and 3rd question?
 
OK, you have 12 km/h and you want to convert it to m/s. First, note that

[tex]1~\mbox{km} = 1000~\mbox{m} \rightarrow \frac{1000~\mbox{m}}{1~\mbox{km}} = 1[/tex]

Since multiplying by 1 doesn't change anything, you have

[tex]12 \frac{\mbox{km}}{\mbox{h}} = 12 \frac{\mbox{km}}{\mbox{h}}\times \frac{1000~\mbox{m}}{1~\mbox{km}}[/tex]

Now the km in the numerator of the first factor cancels with the km in the denominator of the second, leaving you with

[tex]12 \frac{\mbox{km}}{\mbox{h}} = 12000 \frac{\mbox{m}}{\mbox{h}}[/tex]

You do the same sort of thing to change the h in the bottom to s, using the conversion factors

[tex]1~\mbox{h} = 60~\mbox{min}[/tex]

[tex]1~\mbox{min} = 60~\mbox{s}[/tex]
 
Yes, thanks.
And my answer are 12000m/3600s
The question said, i need to change it to standard form.
Do you have any idea on how to convert 12000m/3600s to standard form?
This is the part which i actually stuck at.

By using scientific calculator, my calculator showed this
12000m/3600s = 3.33333 which is endless.
I found this is the wrong way to solve the question.

So i gave my try on the second method in mind.
converting 12000m to standard form give me 1.2 x 10(to the power of)4
converting 3600s to standard form give me 3.6 x 10(to the power of)3
Now I'm stuck at this step again.
1.2 x10(to the power of)4 / 3.6 x 10(to the power of)3
I can't seems to give the answer in standard form as i think this is the wrong way too.

So, any ideas on how to change the answer to standard form?
 
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You just have to truncate the number at the correct number of significant figures. The original figure was 12 km/h, which has two significant figures, so the answer would be 3.3 m/s. If it had been 12.00 km/h, you'd write 3.333 m/s.

You don't need to include a power of 10 when the exponent would be zero.
 
Ok, i get it now. Thanks for every effort you put in this thread :) Appreciate your help so much. ^^
 

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