Help With Simple Single Slit Diffraction Pattern?

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The discussion centers on calculating the wavelength of light using the single slit diffraction formula, given a slit width of 2.45 cm and the angle of the second dark fringe at 44.3°. The user converted the angle to radians and attempted to solve for the wavelength using the equation θ = pλ/a. There is confusion regarding the expected units for the wavelength, whether in nanometers or meters. Additionally, a comment highlights that the slit width is quite large, which may affect the visibility of diffraction patterns. The conversation emphasizes the need for clarity on both the calculation and the physical implications of the slit size.
bmb2009
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Homework Statement


Plane light waves are incident on a single slit of width 2.45 cm. The second dark fringe is observed at 44.3° from the central axis. What is the wavelength of the light?


Homework Equations


θ=pλ/a... where theta is in radians, p =2 (second light minimum), and a = slit width

this seems like it should be a simple problem but I can't get the answer..any Help?


The Attempt at a Solution


I tried

44.3°=.7732 rad so .7732=(2)(λ)/.0245 and solved for λ. Also, does come out in nano meters or meters?

Thanks for your help!
 
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bmb2009 said:

Homework Statement


Plane light waves are incident on a single slit of width 2.45 cm. The second dark fringe is observed at 44.3° from the central axis. What is the wavelength of the light?


Homework Equations


θ=pλ/a... where theta is in radians, p =2 (second light minimum), and a = slit width

this seems like it should be a simple problem but I can't get the answer..any Help?


The Attempt at a Solution


I tried

44.3°=.7732 rad so .7732=(2)(λ)/.0245 and solved for λ. Also, does come out in nano meters or meters?

Thanks for your help!

That is a very wide slit if you are expecting to notice diffraction of light.!
 
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