Solving Implicit O.D.E: sin(y) + xy - x^3 = 2 | 2nd Order ODE Help

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Is, sin(y) + xy - x^3=2, an implicit soln to the 2nd order ODE y''= {6xy' + (y')^3 * sin(y) - 2(y')^2}/ (3x^2 - y)?
 
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Have you tried it? If sin(y) + xy - x^3=2 then cos(y)y'+ y+ xy'- 3x^2= 0. Differentiating again, -sin(y)(y')^2+ cos(y)y''+ 2y'+ xy''- 6x= 0.

You can you those to see if the differential equation is satisfied or not.
 
thanks.
 
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