Help With Tensors: Solving a Problem

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The discussion centers on solving a problem involving the inertia tensor of three equal mass points located at coordinates (a,a), (a,−a), and (−a,−a) with z=0. The inertia tensor is expressed as I = ma²(3ii − ij − ji + 3jj + 6kk), and the task involves finding the principal axes u1, u2, and u3. The solution requires diagonalizing the inertia matrix to find eigenvalues, which leads to the conclusion that the products of inertia with respect to the new axes are zero.

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This discussion is beneficial for physics students, mechanical engineers, and anyone studying rigid body dynamics or working with inertia tensors in their projects.

atomicpedals
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I'm very clearly not understanding something, if someone could help me put my finger on what that something is. So here's what I've got:

Problem: Three equall mass points (mass m) are located at (a,a) (a,‐a) and (‐a,‐a) (all have z=0).

a) Show I = ma^2 (3ii − ij − ji + 3jj + 6kk)

I11 I12 I13
I = ma^2 I21 I22 I23
I31 I32 I33

I11 I12 0
I = ma^2 I21 I22 0
0 0 I33

3 −1 0
I= ma^2 −1 3 0
0 0 6

I = ma2 (3ii − ij − ji + 3jj + 6kk)

b) Find the principle set of axes u1, u2, and u3 in terms of I, j, and k.
Note: I’m totally sure what exactly to go for...

c) Show
I=ma2(4u1u1 +2u2u2 +6u3u3)
= ma2 (3ii − ij − ji + 3jj + 6kk)
= ma2 [Aii + Bjj + Ckk]
= ma2[4ii + 2jj+ 6kk]
=ma2(4u1u1 +2u2u2 +6u3u3)

d) Show by explicit calculation that the products of inertia with respect to the new
axes are zero.

This solution follows from part b, once I get part b hammered out this will then follow.
 
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For part b) you want to diagonalize your matrix, i.e. find the eigenvalues. Since inertia tensors are symmetric they are diagonalizable.
 

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