Hg in U-shape tube, water is added. final h Hg?

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In a U-shaped tube containing mercury (Hg), adding 11.2 cm of water to one side creates a pressure difference that causes the mercury to rise in the opposite side. The problem involves applying the hydrostatic pressure equation, p = p + ρgh, to determine the height change of the mercury. The weight of the water exerts pressure on the mercury, which must be balanced by the pressure exerted by the height of the mercury column. Initial calculations should focus on the balance of forces, treating the system like a teeter-totter. Understanding this balance is crucial for solving the problem accurately.
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Homework Statement



A U shaped container containing Hg at rest. 11.2 cm of water is added to the right side of container. How much does the Hg rise?


Homework Equations



p = p + \rhogh



The Attempt at a Solution

 
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Welcome to the PF, locster! An important PF rule is that you need to show some of your initial work in order for us to offer you some tutorial help. What are your initial thoughts on how to approach this problem? Hint -- the water will not diffuse through the water to any great extent, so the water is only significant for its weight down on one surface of the mercury. Think of it as a teeter-totter with weights on the ends -- what is the balance condition?
 

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