High Pass Filter RL circuit: Time/Frequency Response

In summary, the conversation is about finding the time domain response, input/output transfer function, and graphs for circuit B on page 2. The solution involves using Thevenin's theorem and treating the inductor as an impedance. The transfer function can be simplified and then used to generate a bode plot for different values of frequency. The conversation ends with a suggestion to check a website for further explanation.
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aznkid310
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Homework Statement



For circuit B on page 2, find:

a) the time domain response v0 for a unit step input
b) input/output transfer function T(s) = v0/v_in
c) plot v0 vs. time
d) plot sinusoidal steady state vs. frequency: the magnitude in dB and phase in degrees of T(s)


Homework Equations



I'm getting stuck am an not sure how to proceed. Can someone check my work and also guide me along?


The Attempt at a Solution



a)R_thev = (2.2k)(1k)/(2.2k + 1K) = 687.5 ohms

V = 2.2k*v_in/(1k + 2.2k) [voltage divider]

tau = time constant = L/R_thv = 1.45454e-5

Then vo = .6875(1-e^(-t/tau)) = .6875(1-e^(-68750t)) assuming v_in = 1

T(s) = v0/v_in, where v0 = Z_eq/(Z_eq + 1K), Z_eq = (jwL)(2.2k)/(jwl + 2.2k)

My problem is converting this into a usable form to graph.
 

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Sorry, I didn't follow your use of Thevenin's theorem. You are on the right track treating the inductor as an impedance of ##Z_L = j \omega L##. Your transfer function is correct as far as you have taken it, but it can be further simplified. The transfer function is just a complex number that depends on ##\omega##. You will just use the magnitude and phase formulas for a complex number to generate your graph (bode plot) for different values of ##\omega##. Maybe this website will help explain it.
 
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1. What is a high pass filter RL circuit?

A high pass filter RL circuit is an electrical circuit that allows high frequency signals to pass through while blocking low frequency signals. It consists of a resistor (R) and an inductor (L) connected in series.

2. How does a high pass filter RL circuit work?

A high pass filter RL circuit works by using the properties of the inductor to oppose changes in current. At low frequencies, the inductor acts as a short circuit, allowing the signal to pass through. At high frequencies, the inductor's impedance increases, blocking the signal and allowing only the resistor to pass the signal.

3. What is the time response of a high pass filter RL circuit?

The time response of a high pass filter RL circuit is exponential. When a step input is applied, the circuit takes some time to reach its steady state, which is determined by the values of the resistor and inductor. The time constant (τ) of the circuit is equal to the product of the resistance and inductance (τ = L/R).

4. What is the frequency response of a high pass filter RL circuit?

The frequency response of a high pass filter RL circuit shows how the output voltage varies with different input frequencies. At low frequencies, the output voltage is approximately the same as the input voltage. As the frequency increases, the output voltage decreases, and the circuit acts as a high-pass filter, blocking low frequency signals.

5. What are the practical applications of a high pass filter RL circuit?

High pass filter RL circuits are commonly used in audio systems to filter out low frequency noise and improve the overall sound quality. They are also used in communication systems to transmit high frequency signals without interference from low frequency signals. Additionally, they are used in power supplies to block unwanted AC noise while allowing the desired DC signal to pass through.

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