High Pass Filter RL circuit: Time/Frequency Response

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SUMMARY

The discussion focuses on analyzing a high pass filter RL circuit, specifically circuit B, to determine its time domain response, transfer function, and frequency response. The user successfully calculated the Thevenin equivalent resistance (R_thev) as 687.5 ohms and derived the time constant (tau) as 1.45454e-5 seconds. The transfer function T(s) was established as v0/v_in, with v0 expressed in terms of the equivalent impedance Z_eq. Further simplification of the transfer function is necessary for effective graphing of the magnitude and phase in a Bode plot.

PREREQUISITES
  • Understanding of RL circuits and their time/frequency responses
  • Familiarity with Thevenin's theorem and impedance calculations
  • Knowledge of Bode plots and complex number representation
  • Proficiency in using Laplace transforms for circuit analysis
NEXT STEPS
  • Learn how to derive and simplify transfer functions for RL circuits
  • Study the application of Bode plots for frequency response analysis
  • Explore the use of Laplace transforms in circuit analysis
  • Investigate online resources for visualizing complex numbers and their implications in circuit design
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing and designing RL filter circuits will benefit from this discussion.

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Homework Statement



For circuit B on page 2, find:

a) the time domain response v0 for a unit step input
b) input/output transfer function T(s) = v0/v_in
c) plot v0 vs. time
d) plot sinusoidal steady state vs. frequency: the magnitude in dB and phase in degrees of T(s)


Homework Equations



I'm getting stuck am an not sure how to proceed. Can someone check my work and also guide me along?


The Attempt at a Solution



a)R_thev = (2.2k)(1k)/(2.2k + 1K) = 687.5 ohms

V = 2.2k*v_in/(1k + 2.2k) [voltage divider]

tau = time constant = L/R_thv = 1.45454e-5

Then vo = .6875(1-e^(-t/tau)) = .6875(1-e^(-68750t)) assuming v_in = 1

T(s) = v0/v_in, where v0 = Z_eq/(Z_eq + 1K), Z_eq = (jwL)(2.2k)/(jwl + 2.2k)

My problem is converting this into a usable form to graph.
 

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Sorry, I didn't follow your use of Thevenin's theorem. You are on the right track treating the inductor as an impedance of ##Z_L = j \omega L##. Your transfer function is correct as far as you have taken it, but it can be further simplified. The transfer function is just a complex number that depends on ##\omega##. You will just use the magnitude and phase formulas for a complex number to generate your graph (bode plot) for different values of ##\omega##. Maybe this website will help explain it.
 
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