High speed train sounding horn - Doppler effect

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SUMMARY

The discussion focuses on calculating the perceived frequency of a sound emitted by a high-speed train traveling at 41 m/s with a horn frequency of 416 Hz. The correct formula to use is f0 = fs / (1 + vs/v) when the source is moving away from the observer. Applying this formula with the speed of sound at 345 m/s results in a perceived frequency of approximately 366.6 Hz. The initial misunderstanding stemmed from using the wrong sign in the denominator of the equation.

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A high speed train is traveling at a speed of 41 m/s when the engineer sounds the 416 Hz warning horn. The speed of sound is 345 m/s. What is the frequency of the sound as perceived by a person standing on at the crossing when the train is leaving?

I used the equation: f0=fs/(1-vs/v)
f0=416 Hz / 1-(41 m/s / 345 m/s)
f0=366.6

I'm not sure what I'm doing wrong... =(
 
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You want to find the observed frequency for when the train is moving away from the observer. When the source is moving away from the observer, the sign in the denominator is positive, not negative. That is you problem.
 
oh okay thanks!
 
No problem. :smile:
 

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