High Temperature Limit of Entropy in a Two Level System

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SUMMARY

The discussion focuses on calculating the high temperature limit of entropy in a two-level system, specifically demonstrating that the entropy is given by the formula ##S = Nk\ln(2)##. Participants clarify that the number of configurations, ##\Omega##, is calculated using the formula ##\Omega = \frac{N!}{(\frac{N}{2})!(\frac{N}{2})!}##. The Stirling approximation is applied to simplify the logarithmic expressions, leading to the conclusion that the entropy at high temperatures is indeed ##Nk\ln(2)##. A common error identified involves a missing minus sign in the logarithmic transformation.

PREREQUISITES
  • Understanding of statistical mechanics principles
  • Familiarity with Stirling's approximation
  • Knowledge of entropy and its mathematical representation
  • Basic combinatorial mathematics for calculating configurations
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  • Study the application of Stirling's approximation in statistical mechanics
  • Explore the derivation of entropy in various thermodynamic systems
  • Learn about the implications of two-level systems in quantum mechanics
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Students and professionals in physics, particularly those studying thermodynamics and statistical mechanics, as well as anyone interested in the mathematical foundations of entropy in two-level systems.

Kara386
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Homework Statement


Sounds like a physics problem but I'm sure of the physics, stuck on the maths. At high T a two level system has ##\frac{N}{2}## particles in each level. If entropy is given by ##S = k\ln(\Omega)##, where ##\Omega## is the number of ways of getting ##\frac{N}{2}## particles per level, show the high temperature limit is ##Nk\ln(2)##.

Homework Equations

The Attempt at a Solution


To the best of my knowledge, ##Omega = \frac{N!}{(\frac{N}{2})!(\frac{N}{2})!}##. Taking ##ln## of this and using the Stirling approximation:

##N\ln(N) - N - [\frac{N}{2}\ln(\frac{N}{2}) - \frac{N}{2}] - [\frac{N}{2}\ln(\frac{N}{2})-\frac{N}{2}]##
##= N\ln(N) - N\ln(\frac{N}{2})##
## = -Nln(2)##
I've gone wrong with a minus sign somewhere but I really can't see where! Thanks for any help!
 
Physics news on Phys.org
How do you write ##-N \ln(N/2)## as a sum of two logarithms?
 
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DrClaude said:
How do you write ##-N \ln(N/2)## as a sum of two logarithms?
Oh yes, there's the missing minus sign. Thank you! :)
 

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