(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A puck of mass 7 kg moving at 3 m/s strikes an identical puck that is stationery on frictionless ice. After the collision, the first puck leaves with a speed of v1 at an angle of 41.1647 degrees with respect to its original line of motion and the second puck leaves with a speed of v2 at 48.8353 degrees.

2. Relevant equations

MaVa + MbVb = MaVa' + MbVb'

3. The attempt at a solution

Puck along x-axis:

MVa = MVa' * Cos 41.1647 + MVb' * Cos -48.8353

y-axis:

0 = MVa' * Sin 41.1647 + MVb' * Sin -48.8353

I solved for Va' and got 1.844 (rounded to 3 decimal places), but that answer is wrong. What did I do wrong?

**Physics Forums - The Fusion of Science and Community**

# Hockey puck momentum/ collision

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Hockey puck momentum/ collision

Loading...

**Physics Forums - The Fusion of Science and Community**