A puck of mass 7 kg moving at 3 m/s strikes an identical puck that is stationery on frictionless ice. After the collision, the first puck leaves with a speed of v1 at an angle of 41.1647 degrees with respect to its original line of motion and the second puck leaves with a speed of v2 at 48.8353 degrees.
MaVa + MbVb = MaVa' + MbVb'
The Attempt at a Solution
Puck along x-axis:
MVa = MVa' * Cos 41.1647 + MVb' * Cos -48.8353
0 = MVa' * Sin 41.1647 + MVb' * Sin -48.8353
I solved for Va' and got 1.844 (rounded to 3 decimal places), but that answer is wrong. What did I do wrong?