Hockey Question: How Far Does Crazy Chretien Slide?

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SUMMARY

The problem involves a 0.4 kg hockey puck traveling at 80 m/s, caught by goalie "Crazy Chretien," who has a mass of 90 kg and a coefficient of friction of 0.05. Using the conservation of momentum, the speed of Chretien after catching the puck is calculated to be approximately 0.3556 m/s. The distance he slides before stopping is determined using the work-energy principle, yielding a result of 0.13 meters. The discussion highlights the significance of the puck's mass and speed in the context of hockey physics.

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Homework Statement



"Rockey Bourchard" sends a 0.4 kg puck at 80 m/s which is caught by goalie "Crazy Chretien" who is stationary on his knees on the ice. If the coefficient of friction of Chretien on the ice is 0.05, and his total mass is 90 kg, how far does he slide on the ice before coming to a stop?


Homework Equations



mv = mv' (conservation of momentum)
W = (delta)Ek

The Attempt at a Solution



Alright guys, I was just wondering if you can confirm this as the proper solution.
So first I found the momentum of the puck:

p = mv = (0.4kg)(80m/s) = 32 kg m/s

Since momentum is conserved, we can find the speed of the puck as it hits Chretien

v = p'/m = (32 kg m/s)/(90 kg) = 0.3556 m/s

With the equation "W = (delta)Ek"
I change it to " -F * d = 0.5mv2^2 - 0.5 m v1^2 "
and since v2 = 0 and the -F * d becomes ' μmgd', I got the equation
-μmgd = -0.5mv1^2

Solve for d:

d = (v1^2)/(2μg) = (0.3556 m/s)^2/(2*0.05*9.8m/s^2) = 0.13 m
 
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Looks good except that the mass of the hockey player holding the puck is 90.4 rather than 90.
 
I am not sure why they are interested in the goalie. The puck is 2.5 times the weight of a normal hocky puck and moving twice as fast as the fastest NHL slapshot. So whoever shot this puck is the guy we should be interested in.:)

AM:
 

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