Hollow sphere rolling up a ramp

Click For Summary

Homework Help Overview

The problem involves a hollow sphere rolling along a horizontal surface and transitioning to a 30-degree incline. The objective is to determine how far the sphere travels up the incline before it reverses direction, with an emphasis on the conservation of energy principles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using conservation of energy to solve the problem, with one noting the relationship between linear velocity and angular velocity for rolling objects. Questions arise regarding the rotational inertia of the hollow sphere and the necessity of knowing the radius for calculations.

Discussion Status

The discussion is active, with participants providing guidance on the method and exploring the implications of rolling without slipping. There is acknowledgment of the relationship between linear and angular velocity, but uncertainty remains regarding the need for the sphere's radius.

Contextual Notes

Participants are considering the conditions for rolling without slipping and the implications of the sphere's rotational inertia, but the specific radius of the sphere is not provided, leading to questions about its necessity in the calculations.

mjolnir80
Messages
54
Reaction score
0

Homework Statement


a hollow sphere is rolling long a horizontal floor at 5 m/s when it comes to a 30 degree incline. how far up the incline does it roll before reversing direction?

Homework Equations


The Attempt at a Solution


it seems like conservation of energy would work best for this problem
1/2mv^2 + 1/2I\omega^2 = mgh
im just having some problems finding \omega
am i doing this right? and if so any clues on how to find \omega?
thanks in advance
 
Physics news on Phys.org
Assuming the sphere is rolling without slipping, ω and v are directly related. (What's the condition for rolling without slipping?) What's the rotational inertia of a hollow sphere?

Your method is fine.
 
v=\omegar right? but we don't have the radius of the sphere
or do we....?
 
mjolnir80 said:
v=\omegar right?
Right.
but we don't have the radius of the sphere
or do we....?
Maybe you don't need it. :wink: (Just call it "r" and see what happens.)
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 42 ·
2
Replies
42
Views
4K
Replies
8
Views
4K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
3K
  • · Replies 32 ·
2
Replies
32
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 6 ·
Replies
6
Views
6K