Hollow sphere rolling up a ramp

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SUMMARY

The discussion focuses on a physics problem involving a hollow sphere rolling up a 30-degree incline with an initial velocity of 5 m/s. Participants confirm that conservation of energy is the appropriate method to solve the problem, utilizing the equation 1/2mv^2 + 1/2Iω^2 = mgh. The relationship between linear velocity (v) and angular velocity (ω) is established as v = rω, where the radius (r) of the sphere is not explicitly needed for the solution. The rotational inertia of a hollow sphere is also a key consideration in the calculations.

PREREQUISITES
  • Understanding of conservation of energy principles in physics
  • Familiarity with rotational motion concepts, including angular velocity and inertia
  • Knowledge of the relationship between linear and angular motion (v = rω)
  • Basic understanding of geometry related to inclines and angles
NEXT STEPS
  • Study the conservation of energy in rotational dynamics
  • Learn about the rotational inertia of different shapes, focusing on hollow spheres
  • Explore the concept of rolling without slipping and its implications in physics problems
  • Practice solving similar problems involving inclined planes and rolling objects
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of energy conservation and rotational motion in real-world applications.

mjolnir80
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Homework Statement


a hollow sphere is rolling long a horizontal floor at 5 m/s when it comes to a 30 degree incline. how far up the incline does it roll before reversing direction?

Homework Equations


The Attempt at a Solution


it seems like conservation of energy would work best for this problem
1/2mv^2 + 1/2I\omega^2 = mgh
im just having some problems finding \omega
am i doing this right? and if so any clues on how to find \omega?
thanks in advance
 
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Assuming the sphere is rolling without slipping, ω and v are directly related. (What's the condition for rolling without slipping?) What's the rotational inertia of a hollow sphere?

Your method is fine.
 
v=\omegar right? but we don't have the radius of the sphere
or do we....?
 
mjolnir80 said:
v=\omegar right?
Right.
but we don't have the radius of the sphere
or do we....?
Maybe you don't need it. :wink: (Just call it "r" and see what happens.)
 

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