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Home school Calculas( high school level)

  1. May 6, 2007 #1
    Hi.. New at this site, hope I'm posting these stuff on the write place....
    well i had these question below for review for an exam, hope someone can help me solve them, i did my solution in Paint program and on paper and am linking where i uploaded them, ( image shack)

    -Find the second derivative

    ** for where 'e^-x' i think the question is wrong,, i think it should be e^x, not sure??

    3)Find the second derivative of 'y' with respect to "x" where

    4)Find the equation of 2 lines, each of slope 5, that are tangent to y=x^3+2X

    5) Find the asymptotes for

    6)A dragster accelerates down a strip adn then brakes, adn comes to stop. Its position function, s(t) is given by s(t)=3t^2-1/5t^3, s'(t) in meters, 't' in seconds
    a) when does the dragster come to a stop
    b) how far has the dragster traveled.

    7) Find the polynomial with second degree that goes through (1,-1) and whose slope is 1, When x=-1 and where slop is 19, when x=2

    8) A helicopter takes off from landing pad at 10:48AM and travels south at 150KM/h is planning to land at 10:56AM.
    a) how far is the distance between them changing at 10:50AM( to 2 decimal place)
    b) Is the distance between them increasing or decreasing at this instant?

    I couldn't answer 4,5,8... please help me with them...and check solution
    thank you ...
  2. jcsd
  3. May 6, 2007 #2
    For #4, the derivative is a quadratic. There are 2 places where the tan line has a slope of 5. Find the points where it equals 5 (or where that minus 5 equals zero) and then you have 2 points and 2 slopes
  4. May 6, 2007 #3
    8. If he's traveling at 150 km/h, then that's how fast the distance is changing. For b, it depends. If it went past his destination before 10:50, then the distance is increasing, otherwise it's decreasing.
  5. May 6, 2007 #4
    For quadratic equation i would need a,b and c. but i have only 2 numbers......and how would i find the point where the point equals 5?

    Also can anyone check the solutions i did,

  6. May 7, 2007 #5


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    "For quadratic equation i would need a,b and c. but i have only 2 numbers......and how would i find the point where the point equals 5? "
    A "point" can't equal 5! You are looking for the value of x such that the derivative 3x2+ 2= 5. Surely you can solve that equation.
  7. May 7, 2007 #6
    For #1 the final answer(first derivative) is [tex](e^{4x} \cdot 2x^2) \cdot (4x+3)[/tex] not 2x + 3...you multiplyed by 2 insted 4...

    Edit...even more simple it is if you leave it like this [tex]6x^2 e^{4x} + 8x^3 e^{4x}[/tex] and make a second derivative...
    Last edited: May 7, 2007
  8. May 7, 2007 #7
    I factored out the 2x^2, if you factor it back in , you get the same result....So confused,,,dont know where i made mistake sorry sorry,,,,,,,could you show me where i made the mistake,,,

    thank you everyone for your help:)
  9. May 10, 2007 #8
    You multiplied it wrongly...
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