Homework Question - Beta and Alpha decay

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Homework Help Overview

The discussion revolves around a question related to nuclear decay processes, specifically beta and alpha decay, involving the radioactive isotope of bismuth (Bi-213). The original poster seeks validation of their understanding and calculations regarding the transformations of the nucleus during these decay processes.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to outline the decay steps and their effects on the nucleon and proton numbers, while others question the accuracy of the intermediate symbols used and whether detailed nuclear reactions are necessary.

Discussion Status

Participants are actively engaging with the original poster's reasoning, providing feedback on the correctness of the calculations and the notation used. There is a mix of agreement and suggestions for clarification, indicating a productive exchange of ideas without reaching a definitive conclusion.

Contextual Notes

Some participants note the informal nature of the original poster's notation and discuss the importance of using correct symbols in formal contexts. There is also mention of the original poster's intent to explore further topics related to leptons in future questions.

LotusTK
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Hi, i am new here. Thought it would be good to sign up as i have just started hitting the books in preparation for my AS Level exams. So this is my first question.

I think i may have done this question correctly, but i was just seeing what other people think as i am not 100% sure about it.

Question:

A nucleus of the radioactive isotope of bismuth Bi (213) and (83) emits a beta particle, then an alpha particle, then another beta particle before it becomes stable.

a) Show that the stable nucleus formed is a Bismuth isotope

My Attempt at it

Bi (213) (83) → Bi (213) (84) I have added one to the proton number, because in beta decay, a neutron turns into a proton, so the nucleon number remains the same, but the proton number goes up by 1.

Then for Alpha, it becomes Bi (209) (82). I have taken 4 from the nucleon number and 2 from the proton number because an alpha particle consists of 2 protons and 2 neutrons.

Then after the second beta decay i ended up with Bi (209) (83).

Is this correct?

Thanks for your help.
 
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Looks good, but I'm not sure whether they're expecting you to write step by step proper nuclear reactions (including the electrons and antineutrinos and the alpha particles ).
 
I agree with the numbers, but the symbols of the intermediate nuclei are not "Bi".
 
Thanks for the replies.

Curious3141, i don't think you do have to, but i know how to if i were to be asked in an exam. Just write B (0) (-1) add the anti neutrino (the v with the line above it) to the beta decay, and fore alpha, write the alpha symbol with (4) (2).

mfb, I just used "Bi" as that was the element quoted in the question. I know that the elements that are formed inbetween are not "Bi".

Expect me to ask more questions later on, as i will be starting to revise Leptons and all of that stuff that I am really weak with. :D
 
LotusTK said:
Thanks for the replies.

Curious3141, i don't think you do have to, but i know how to if i were to be asked in an exam. Just write B (0) (-1) add the anti neutrino (the v with the line above it) to the beta decay, and fore alpha, write the alpha symbol with (4) (2).

mfb, I just used "Bi" as that was the element quoted in the question. I know that the elements that are formed inbetween are not "Bi".

Expect me to ask more questions later on, as i will be starting to revise Leptons and all of that stuff that I am really weak with. :D

No, but mfb is right - in writing that way, it's wrong. It's OK to omit the symbol entirely (if you're just writing informally), but to actually put "Bi" there is wrong.
 
The proton number?
 
LotusTK said:
The proton number?

Steamking's post (that you're replying to) has vanished. But you're correct. I prefer to refer to it as the atomic number, because that's a good reminder that this is the number that determines what atom it is.
 

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