Homomorphism Help: Show det(A) is a Homomorphism to R*

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SUMMARY

The determinant mapping from GL(2,R) to R*, defined as A -> det(A), is confirmed to be a homomorphism. This is established by the property that det(AB) = det(A)det(B), which directly satisfies the homomorphism condition. The kernel of this mapping is identified as SL(2,R), the group of 2x2 matrices with determinant equal to one. Understanding these relationships is crucial for grasping the structure of linear transformations in this context.

PREREQUISITES
  • Understanding of group theory, specifically homomorphisms
  • Familiarity with the general linear group GL(2,R)
  • Knowledge of the special linear group SL(2,R)
  • Proficiency in matrix operations and properties of determinants
NEXT STEPS
  • Study the properties of homomorphisms in group theory
  • Explore the structure and significance of the general linear group GL(2,R)
  • Learn about the special linear group SL(2,R) and its applications
  • Investigate the implications of the determinant in linear transformations
USEFUL FOR

Mathematicians, students of abstract algebra, and anyone studying linear algebra and group theory will benefit from this discussion.

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Homework Statement



let R* be the group of nonzero real numbers under multiplication. then the determinant mapping A-> det(A) is a homomorphism from GL(2,R) to R*. the kernel of the determinant mapping is SL(2,R).
i am suppose to show that this is a homomorphism but i have no idea where to go and what to do

Homework Equations


det(AB) = det(A)det(B)

The Attempt at a Solution

 
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If you don't realize that det(AB)=det(A)det(B) basically proves that it is a homomorphism, you might want to look up the definition of homomorphism and think about it.
 

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