Hooke's law and wave velocity related problem

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harini07
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Homework Statement


The extension in a string, obeying hooke’s law is Y when wave velocity in it is V. if extension is increased to 1.5Y, then wave velocity V’ becomes?

1) V' =V. 2)V'= 1.22V . 3)V'=1.5V. 4) V'=0.75V.

Homework Equations


wave velocity= frequency*wave length.

The Attempt at a Solution


the frequency will be unchanged in both the cases, so v/v' = Y/1.5Y , which gives V'= 1.5V. but this is not the answer. where did i go wrong?
 
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harini07 said:
The extension in a string, obeying hooke’s law is Y when wave velocity in it is V.
Do you mean tension?
 
DrClaude said:
Do you mean tension?
nope. it's the extension and not tension.
 
So your are simply changing the length of the string.
harini07 said:
the frequency will be unchanged in both the cases
Have you ever played a guitar (or seen someone playing one)?
 
DrClaude said:
So your are simply changing the length of the string.

Have you ever played a guitar (or seen someone playing one)?
except in movies no.
 
Think about how someone changes the notes on a guitar.

By the way, it would be helpful if you came up with more "relevant equations."
 
DrClaude said:
Think about how someone changes the notes on a guitar.

By the way, it would be helpful if you came up with more "relevant equations."
in particularly? there is this hooke's law which states F(force) = -K(spring constant)*x (extension). how to relate this with wave velocity?
 
I realize now that the problem statement is not clear. How is the extension changed? By taking a longer length of the same string, or stretching it? I was assuming the former.
 
Chestermiller said:
Do you know the equation for the wave velocity of a string as a function of the string tension? The equation has to take into account the fact that the string has mass.
Yup. V=√(T/mass per unit length). Substituting T for Y*area*extension/original length. Since the other components like mass, length,Young's modulus,area are unchanged, I'm equating V/V' =√(y/1.5y). Which gives V/V' = 0.82. thus I'm getting V' = 1.21V. Is this method correct?
 
harini07 said:
Yup. V=√(T/mass per unit length). Substituting T for Y*area*extension/original length. Since the other components like mass, length,Young's modulus,area are unchanged, I'm equating V/V' =√(y/1.5y). Which gives V/V' = 0.82. thus I'm getting V' = 1.21V. Is this method correct?
Yes.
 
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