Hooke's law and wave velocity related problem

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Homework Help Overview

The problem involves understanding the relationship between the extension of a string, as described by Hooke's law, and the wave velocity in that string. The original poster presents a scenario where the extension is increased and seeks to determine the resulting change in wave velocity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the implications of changing the extension of the string and its effect on wave velocity. There are questions about whether the change refers to tension or extension, and how these relate to wave properties.

Discussion Status

Participants are exploring various equations related to wave velocity and tension, with some suggesting the need for clearer definitions and assumptions regarding the problem setup. There is an ongoing examination of the relationships between the variables involved.

Contextual Notes

There is some ambiguity regarding how the extension is altered—whether by changing the length of the string or by stretching it. This uncertainty affects the interpretation of the problem and the equations being discussed.

harini07
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Homework Statement


The extension in a string, obeying hooke’s law is Y when wave velocity in it is V. if extension is increased to 1.5Y, then wave velocity V’ becomes?

1) V' =V. 2)V'= 1.22V . 3)V'=1.5V. 4) V'=0.75V.

Homework Equations


wave velocity= frequency*wave length.

The Attempt at a Solution


the frequency will be unchanged in both the cases, so v/v' = Y/1.5Y , which gives V'= 1.5V. but this is not the answer. where did i go wrong?
 
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harini07 said:
The extension in a string, obeying hooke’s law is Y when wave velocity in it is V.
Do you mean tension?
 
DrClaude said:
Do you mean tension?
nope. it's the extension and not tension.
 
So your are simply changing the length of the string.
harini07 said:
the frequency will be unchanged in both the cases
Have you ever played a guitar (or seen someone playing one)?
 
DrClaude said:
So your are simply changing the length of the string.

Have you ever played a guitar (or seen someone playing one)?
except in movies no.
 
Think about how someone changes the notes on a guitar.

By the way, it would be helpful if you came up with more "relevant equations."
 
DrClaude said:
Think about how someone changes the notes on a guitar.

By the way, it would be helpful if you came up with more "relevant equations."
in particularly? there is this hooke's law which states F(force) = -K(spring constant)*x (extension). how to relate this with wave velocity?
 
  • #10
I realize now that the problem statement is not clear. How is the extension changed? By taking a longer length of the same string, or stretching it? I was assuming the former.
 
  • #11
Do you know the equation for the wave velocity of a string as a function of the string tension? The equation has to take into account the fact that the string has mass.
 
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  • #12
Chestermiller said:
Do you know the equation for the wave velocity of a string as a function of the string tension? The equation has to take into account the fact that the string has mass.
Yup. V=√(T/mass per unit length). Substituting T for Y*area*extension/original length. Since the other components like mass, length,Young's modulus,area are unchanged, I'm equating V/V' =√(y/1.5y). Which gives V/V' = 0.82. thus I'm getting V' = 1.21V. Is this method correct?
 
  • #13
harini07 said:
Yup. V=√(T/mass per unit length). Substituting T for Y*area*extension/original length. Since the other components like mass, length,Young's modulus,area are unchanged, I'm equating V/V' =√(y/1.5y). Which gives V/V' = 0.82. thus I'm getting V' = 1.21V. Is this method correct?
Yes.
 
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