1. The problem statement, all variables and given/known data Seven and one half foot pounds of work is required to compress a spring 2 inches from its natural length. Find the work required to compress the spring an additional one-half inch 2. Relevant equations W=kd W=∫f(x)dx 3. The attempt at a solution 7.5=W ∫kxdx from (0,1/6) =(kx^(2))/2 from (0,1/6) =k/72=7.5 K=540 ∫(540x)dx from (4/24, 5/24) The rest is just algebra that's irrelevant; did i set up the problem right?