Hookes Law, Finding A Springs Constant

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Homework Help Overview

The discussion revolves around Hooke's Law and the calculation of a spring constant based on the extension of a spring when a mass is attached. The original poster presents a scenario where a spring extends by 10 cm with a 100 g mass, seeking to determine the spring constant.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the necessity of converting mass from grams to kilograms and the implications of using correct units in calculations. There are attempts to clarify the relationship between force, spring constant, and extension, with some participants questioning the original poster's calculations.

Discussion Status

The discussion is ongoing, with participants providing guidance on unit conversion and raising questions about the calculations presented. There is no explicit consensus on the correctness of the original poster's approach, and multiple interpretations of the problem are being explored.

Contextual Notes

Participants emphasize the importance of using standard units in calculations, noting that the original poster's use of grams instead of kilograms may lead to incorrect results. The discussion highlights the need for clarity in unit conversions and the application of Hooke's Law.

kcrawshaw
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A spring extends by 10cm when a mass of 100g is attached to it. What is the spring constant? (calculate your answer in N/m)

I have done this so far but I don't feel that it is right as the Force (F) is in grams and not Newtons:

F = K x E
100 = K x 0.10
100 ÷ 0.10 = 100
K = 100 N/m

Is this right or have I gone wrong somewhere?
Thanks
 
Last edited:
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What's the weight (in Newtons) of a 100 g mass? (Always convert everything to standard units.)
 
F- kx
100g = 100*10 = 1000 Newtons of force.

1000 = -k (-0.1) \implies k = \boxed{10 000}
 
You'll need to convert the weight from g to kg; right now you have the units in (g*m/s^2)/m
N/m is (kg*m/s^2))/m where the unit of Newtons is kg*m/s^2
 
oneplusone said:
F- kx
100g = 100*10 = 1000 Newtons of force.

1000 = -k (-0.1) \implies k = \boxed{10 000}
This is incorrect.

Please allow the OP to solve the problem for themselves.
 

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