Hooke's law = negative spring constant?

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Homework Help Overview

The discussion revolves around Hooke's law and its implications regarding the spring constant and potential energy stored in a spring. The original poster presents a scenario involving a spring's force and displacement, questioning the validity of a negative spring constant derived from their calculations.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between force and displacement in the context of Hooke's law, questioning the interpretation of the spring constant as negative. There are inquiries about the relationship between potential energy and work done, as well as the implications of displacement being a vector quantity.

Discussion Status

Some participants have offered clarifications regarding the vector nature of displacement and its impact on the sign of the spring constant. Others have discussed the conceptual underpinnings of Hooke's law and the significance of the negative sign in the context of forces acting on the spring.

Contextual Notes

There is an acknowledgment of the potential confusion surrounding the definitions and assumptions related to force and displacement in the context of Hooke's law. The discussion also notes that the thread has been active for some time, indicating ongoing engagement with the topic.

scolaiw
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A graph shows the Force of a spring (y axis) against Displacement (x axis) in a linear function. An obvious point for the gradient is the point (0.5 metres, 140 Newtons). What is the spring constant and how much energy is stored in the spring when it is compressed by 0.5 metres?

Hope the description helps.

Hooke's law states: F=-kx

Therefore: 140=-0.5k
Therefore: k=-40/0.5=-80 (But I thought spring constant cannot be negative?)
Also, no idea how to work out energy stored.

Any help will be appreciated! Thanks
 
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scolaiw said:
A graph shows the Force of a spring (y axis) against Displacement (x axis) in a linear function. An obvious point for the gradient is the point (0.5 metres, 140 Newtons). What is the spring constant and how much energy is stored in the spring when it is compressed by 0.5 metres?

Hope the description helps.

Hooke's law states: F=-kx

Therefore: 140=-0.5k
Therefore: k=-40/0.5=-80 (But I thought spring constant cannot be negative?)
Also, no idea how to work out energy stored.

Any help will be appreciated! Thanks
Welcome to physics forums.

Don't forget that displacement, is a vector quantity - i.e. direction matters. In the usual set up, a spring is compressed when x < 0 (i.e. its length decreases). Therefore, if your spring is compressed by 0.5 meters, then x = -0.5.

How is potential energy related to the force (in general)?
 
Thanks for the welcome!

I see about displacement. (Forgot displacement is a vector quantity - sad face)

About the potential energy, is potential energy the same as the work done? So in this case, the area bound by the line and the x-axis from 0 to 0.5 metres?
 
This is one of those Newton's third law issues. If you are talking about the force you exert on the spring to stretch it a distance x, then the force is positive when the displacement is positive, and the force is negative when the displacement is negative. If you are talking about the force that the spring exerts on you when you stretch it a distance x, then the force is negative when the displacement is positive, and the force is positive when the displacement is negative.
 
Mathematics is a tool used by Physicist. We are not bound by it. It does help us to predict what should be the case. Hooke's law describes the relationship between the restoring force of the spring, as experienced by the agent stretching the spring, and the change in length of the spring. The negative sign in this law serves to indicate that the direction of the restoring force and the change in length is in opposite directions. The spring constant is therefore positive - no sense in having a negative constant! If you want to use Hooke's law to calculate the constant you need to take the directions into account.
 
Realize that this thread is years old.
 

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