If, however you assume foot and the board as a joint (so only rotation), then there is a moment. The axis of rotation is the joint, the distance is the y-coordinate of the center of mass. From Newton's second law:
rxF=rxma => M = mr^2 thetaDoubleDot
How you proceed from this point depends on how you model the problem. You can, for instance, assume that there is a maximum resistance moment from the ground that, when surpassed, will make the object (human) fall.
A more realistic way to model it would be to consider a rectangle with a center of mass. There is a maximum angle after which the rectangle will fall over. You can calculate this angle if you consider a line that originates from the point of rotation (so one corner of the rectangle), and that is perpendicular to your surface. If the center of mass goes beyond this line, the rectangle will fall over.
From Newton's law you have a differential equation of motion for your problem, so you can get the angle as a function of acceleration (angle comes into play from the y-coordinate of the "r" vector).
Depending on the initial conditions, you can derive from that the acceleration that causes you to reach that maximum angle.