How Accurate Are These Inverse Laplace Transforms?

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SUMMARY

The inverse Laplace transforms for the given functions Y1(s) = exp(-s)/s^2 and Y2(s) = {1/[4*(s+1)]}*exp(-2*s) are correctly derived using the second shifting theorem. The solutions are y1(t) = (t-1) H(t-1) and y2(t) = (1/4)*exp(2-t)*H(t-2), where H(t) denotes the Heaviside function. The application of the second shifting theorem confirms the accuracy of the solutions provided.

PREREQUISITES
  • Understanding of Laplace transforms
  • Familiarity with the second shifting theorem
  • Knowledge of the Heaviside function
  • Basic differential equations
NEXT STEPS
  • Study the properties of the Heaviside function in detail
  • Learn about the application of the second shifting theorem in Laplace transforms
  • Explore advanced techniques for solving differential equations using Laplace transforms
  • Investigate common Laplace transform pairs and their inverses
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Students and professionals in engineering, mathematics, and physics who are working with differential equations and Laplace transforms, particularly those seeking to deepen their understanding of inverse transforms and the Heaviside function.

Neoon
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Gents,

I have this problem:

find the inverse laplace transfor for

Y1(s) = exp(-s)/s^2

Y2(s) = {1/[4*(s+1)]}*exp(-2*s)

my solution is:

using the 2nd shifting theroem

y1(t) = (t-1) H(t-1)
y2(t) = (1/4)*exp(2-t)*H(t-2)


Is my solution correct?
 
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I want to clarify that H(t-1) and H(t-2) is the Hiviside function.
 
Neoon said:
I want to clarify that H(t-1) and H(t-2) is the Hiviside function.

What is the laplace transform of?
y1(t) = (t-1) H(t-1)
y2(t) = (1/4)*exp(2-t)*H(t-2)
 

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