How can a prime element in a Ring be proven as irreducible?

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SUMMARY

This discussion focuses on proving that a prime element in a Ring is irreducible and establishing the equivalence of the norm of an element being 1 to it being a unit. Participants suggest using proof by contradiction to demonstrate that if a prime element, denoted as p, is assumed to be reducible, it leads to a contradiction. The relationship between the norm of an element and its status as a unit is also explored, emphasizing the importance of understanding invertible elements in this context.

PREREQUISITES
  • Understanding of Ring theory and its properties
  • Familiarity with prime elements and irreducibility in algebra
  • Knowledge of units and invertible elements in mathematical structures
  • Basic concepts of proof techniques, particularly proof by contradiction
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  • Study the properties of prime elements in Rings
  • Learn about proof by contradiction in mathematical arguments
  • Explore the definitions and examples of units in algebraic structures
  • Investigate the implications of norms in the context of Rings
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Mathematicians, algebra students, and educators interested in advanced topics in Ring theory and proofs related to prime elements and units.

NoodleDurh
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How does one show that a prime element in a Ring is irreducible and how does one show that ##|| x || = 1## iff x is a unit.

okay from my knowledge I know that units are invertible elements, so how does the norm of x make it 1... maybe I am not too sure about this
 
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For your first question, try doing a proof by contradiction. Let p be a prime element, and suppose it is reducible. What can you do with that?
 

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