How can I apply the concept of singularity to the matrix AB and BA?

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SUMMARY

In the discussion, it is established that for matrices A (m×n) and B (n×m) where m ≠ n, at least one of the matrices AB or BA is singular. This conclusion arises from the fact that if m < n, the linear transformation represented by A cannot map Rm onto Rn, resulting in a vector in Rn that is not in the image of A. Consequently, (AB)v cannot equal v for such a vector v, confirming the singularity of AB. The argument is similarly valid when n < m by reversing the roles of A and B.

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Homework Statement


I have a trouble in this proof;
Let A be an m[tex]\times[/tex]n matrix and B n[tex]\times[/tex]m matrix. If m[tex]\neq[/tex]n show that at least one of the matrices AB and BA is singular.

Homework Equations



If it is singular not invertible and det=0 but how can I apply this question?

The Attempt at a Solution

 
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First assume that m< n. Then A is a linear transformation from Rm to Rn with m< n and so cannot map Rm onto Rn: it maps Rm into an at most m dimensional subspace of Rn. B maps all of Rn into Rm. Let v be vector in Rn that is NOT in the image of A. (AB)v= A(Bv) is in the image of A and so cannot be equal to v.

If n< m, reverse A and B.
 

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