How can I derive CSC^2 u without using substitution?

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To derive the derivative of CSC^2 u, it is recognized that CSC^2 u can be expressed as (CSC u)^2. The derivative is calculated using the product rule, resulting in 2(CSC u)(CSC u times Cot u). Both substitution and the product rule are valid methods for this derivation, with the final result being (d/du)cosec^2(u) = 2cosec^2(u)cot(u). The discussion confirms that both approaches yield correct results, emphasizing the flexibility in solving the problem.
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Homework Statement



the derivative of CSC u is CSC u times cot u times the derivative of the u
but how can I derive CSC^2 u?


2. The attempt at a solution


CSC^2 u is (CSC u)^2

The derivative is
2(CSC u)(CSC u times Cot u)(1)

another way

CSC^2 u = CSC u times CSC u
CSC u times ( CSC u Cot u )(1) + CSC u ( CSC u Cot u)(1)

Is it correct?
 
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Hi racer! :smile:

Yes they're both right!

(d/du)cosec^2(u) = 2cosec^2(u)cot(u).

You used both substitution and the product rule … they both work in this case, and either is fine. :smile:

(Though personally, I'd always go for substitution.)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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