Integration By Substitution Problem (Trig)

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SUMMARY

The discussion centers on the integration of the function ∫e3tcsc(e3t)cot(e3t) dt using substitution techniques. The user initially attempted a single substitution with u = cot(e3t) but encountered complications due to the csc function not canceling out. A suggestion was made to perform two substitutions, which the user found overwhelming. Ultimately, the user considered converting cotangent and cosecant into their sine and cosine equivalents as a potential solution strategy.

PREREQUISITES
  • Understanding of integration techniques, specifically substitution methods.
  • Familiarity with trigonometric identities, including csc(t) and cot(t).
  • Knowledge of exponential functions and their integration.
  • Ability to manipulate and simplify trigonometric expressions.
NEXT STEPS
  • Learn advanced integration techniques, focusing on multiple substitutions.
  • Study trigonometric identities and their applications in calculus.
  • Explore integration of exponential functions combined with trigonometric functions.
  • Practice problems involving integration by substitution with complex functions.
USEFUL FOR

Students studying calculus, particularly those focusing on integration techniques, as well as educators seeking to enhance their teaching methods for trigonometric integrals.

KingKai
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Homework Statement



Integrate the following using substitution techniques

∫e3tcsc(e3t)cot(e3t) dt

Homework Equations



csc(t) = 1/sin(t)

cot(t) = 1/tan(t)

cot(t) = cos(t)/sin(t)

1 + cot2(t) = csc2(t)

The Attempt at a Solution



∫e3tcsc(e3t)cot(e3t) dt

set u = cot(e3t)

du = (3e3t)(- csc2(e3t)) dt


Make Substitution,


∫e3tcsc(e3t) (u) (1/(3e3t)(- csc2(e3t)) du



Whoops, csc does not cancel out..



My friend told me I had to make TWO substitutions, following this advice my head proceeded to explode.

After recollecting the pieces of my skull fragments and carefully gluing them together again, I posted this question.
 
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KingKai said:

Homework Statement



Integrate the following using substitution techniques

∫e3tcsc(e3t)cot(e3t) dt

Homework Equations



csc(t) = 1/sin(t)

cot(t) = 1/tan(t)

cot(t) = cos(t)/sin(t)

1 + cot2(t) = csc2(t)

The Attempt at a Solution



∫e3tcsc(e3t)cot(e3t) dt

set u = cot(e3t)

du = (3e3t)(- csc2(e3t)) dt


Make Substitution,


∫e3tcsc(e3t) (u) (1/(3e3t)(- csc2(e3t)) du



Whoops, csc does not cancel out..



My friend told me I had to make TWO substitutions, following this advice my head proceeded to explode.

After recollecting the pieces of my skull fragments and carefully gluing them together again, I posted this question.

I would be inclined to turn the cot and csc functions into their sine and cosine equivalents, and go from there.
 

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