How can I derive (G&H)->J using SD rules?

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The discussion revolves around deriving the conclusion (G&H) -> J using standard derivation rules. The original poster expresses difficulty in completing the derivation and seeks assistance. Key points include the importance of starting with the antecedent of the conditional when proving a claim, which the poster initially overlooked. Another participant notes that the first premise, E -> (F -> G), is irrelevant to the derivation. They suggest focusing on deriving I from the assumption (G&H) and emphasize that the argument is valid, as confirmed by a truth table. The conversation highlights the collaborative nature of logic review, with participants providing hints and guidance rather than full solutions, fostering a supportive learning environment.
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Ok, so I'm doing some logic review on my own. It's been awhile since I've done derivations, so I'm a little rusty. I'm just trying to use SD rules and not SD+. I'd appreciate any help you all can offer. Thanks in advance.

Derive: (G&H)->J

1. E->(F->G) assum.
2. H->(G->I) assump
3. (F->I)->(H->J) assump
______________________________________________
4. |E assumption
5. | |G&H assumption
6. | |H 5 &E
7. | |G->I 6,2 ->E
8. | |F->G 4,1 ->E
9. | | |F asummp
10. | | |G 8,9 ->E
11. | | |I 7,10 ->E
12 | | F->I 9-11 ->I
13. | | H->J 3, 12 ->E
14. | | J 6, 13 ->E
15. | (G&H)->J 5-14 ->I



This is where I get stuck. I do get #15 out of the subderivation of E? Or am I going about this all wrong? Can you even derive this thing?

Thanks
 
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Haha, that is a good question to ask. By my check, the tableaux closes without even needing (1). Your proof looks fine, but all you can get out of (4) is ~E or a formula of the form E -> p, e.g., E -> ((G & H) -> J). The key seems to lay with I. You can get I from (2) by assuming (G & H). Can you see how to get a formula from (3) that, effectively, makes you choose between ~I or J?

On second thought, let me put it this way: The only way that F -> I can be false is for I to be ... ??
 
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Rule of thumb: whenever you're trying to prove a conditional claim, the first assumption you make should always be the antecedent of the conditional. You didn't follow this rule; that's why you're having trouble discharging your assumptions at the end.

And the argument is valid: I did a truth-table that shows no row where all premises true and conclusion false.

Derive: (G&H)->J

1. E->(F->G) assum.
2. H->(G->I) assump
3. (F->I)->(H->J) assump
______________________________________________
4. |G&H (assumption)
5. | H 4, &E
6. | G 4, &E
7. | G -> I 2, 5, ->E
8. || F assumption
9. || I 6, 7, ->E
10.| F -> I 8-9, ->I
11.| H -> J 3, 10 ->E
12.| J 11, 5 ->E
13.(G&H) -> J 4-12, ->I QED

Note that the first premise is irrelevant -- I never use it.
 
Hello again, NickJ. :smile: FYI: We aren't allowed to give full solutions here unless the person is having serious problems.
 
Thanks everyone. I appreciate it. You're hint hones helped out greatly. Thanks for taking the time NickJ to write out a sollution, even though you weren't supposed to. :biggrin:

This is a great site, and I'm looking forward to reading and posting here.
 
honestrosewater said:
FYI: We aren't allowed to give full solutions here unless the person is having serious problems.

Oops! Now I know...and knowing is half the battle.
 
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