How can I derive the hydraulic equation using conservation of energy and work?

  • Context: High School 
  • Thread starter Thread starter bdolle
  • Start date Start date
  • Tags Tags
    Derivation Hydraulic
Click For Summary
SUMMARY

The discussion focuses on deriving the hydraulic equation deltaF = rho*g*(A1+A2)d2 using principles of hydrostatics and conservation of energy. The key starting point is equation 5.11, which relates forces and areas in a hydraulic system. The derivation involves substituting variables to express the change in force (deltaF) in terms of the cross-sectional areas (A1, A2) and the height differences (d1, d2). The final formula is confirmed as rho*g*d2*(A1+A2), demonstrating the relationship between force and fluid displacement in hydraulic systems.

PREREQUISITES
  • Understanding of hydrostatics principles
  • Familiarity with the concepts of force and area in fluid mechanics
  • Knowledge of gravitational potential energy
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the derivation of equation 5.11 in hydraulic systems
  • Learn about the principles of conservation of energy in fluid mechanics
  • Explore applications of Pascal's principle in hydraulics
  • Investigate the relationship between pressure, force, and area in fluid systems
USEFUL FOR

Students and professionals in engineering, particularly those specializing in fluid mechanics, hydraulic engineering, and physics, will benefit from this discussion.

bdolle
Messages
10
Reaction score
1
Hey All,

Question about hydraulics. Can't seem to find anyone videos or material to walk me through how to get the formula deltaF = rho*g*(A1+A2)d2

Any takers?

My book states: The conclusion is conservation of evergy. Work is done on the liquid by a small force pushing the liquid through a large displacement. Work is done by the liquid when it lifts the heavy weight through a small distance. a full anaylsis must consider the fact that the graviational potetial energy of the liquid is also changing, so we can't simply equate the output work to the input work. but you can see energy considerations require piston 1 to move farther than piston 2.

As a homework problem you can show that force 1 much increase by ... [insert formula above].

No I can't show it as a homework problem. Been trying for the last 2 hours. I have been searching the internet and can't find any explanations.

Please show me via work and conservation of energy how to derive this formula. Please spell out each step and go slow. Thank you!
 
Physics news on Phys.org
Can you please provide a diagram showing the force that this equation is supposed to be calculating?
 
Chestermiller said:
Can you please provide a diagram showing the force that this equation is supposed to be calculating?

Here you go. Let me know if you need more. Thanks.
 

Attachments

  • IMG_0362.JPG
    IMG_0362.JPG
    37.6 KB · Views: 659
  • IMG_0362.JPG
    IMG_0362.JPG
    37.6 KB · Views: 548
  • IMG_0363.JPG
    IMG_0363.JPG
    52.8 KB · Views: 520
  • IMG_0364.JPG
    IMG_0364.JPG
    46 KB · Views: 529
The solution to your homework problem does not involve energetics. This is strictly a hydrostatics problem. The starting point should be equation 5.11, or, in a slightly different form: $$F_1=F_2\frac{A_1}{A_2}+\rho g h A_1$$The question is "how much does the force F1 have to increase to achieve the new height difference d1+h+d2 (where d1 is the amount that the left level moves down)?"
 
Last edited:
Chestermiller said:
The solution to your homework problem does not involve energetics. This is strictly a hydrostatics problem. The starting point should be equation 5.11, or, in a slightly different form: $$F_1=F_2\frac{A_1}{A_2}+\rho g h A_1$$The question is "how much does the force F1 have to increase to achieve the new height difference d1+h+d2 (where d1 is the amount that the left level moves down)?"

So deltaF = F1 - F1 (where h is changed to (h+d1+d2)).

I get rho*g*A1*(d1+d2)=deltaF. we can sub "d2 = d1A1/A2" like they show in the book... But this will not help us. Instead use "d1=d2A2/A1" and sub this into d1 and we get rho*g*A1*(d2A2/A1+d2) which simplifies to rho*g*d2*(A2+A1) which is what we were looking for.

Got it.

THANKS
 
  • Like
Likes   Reactions: Chestermiller

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 26 ·
Replies
26
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K