How can I do this troglodyte of a series

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Homework Help Overview

The discussion revolves around the convergence of the series (-1)^(n)*n*e^(-2^n). Participants explore various criteria and tests for convergence, particularly focusing on absolute convergence and the behavior of the series' terms.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of the Leibniz criterion for alternating series and question the absolute convergence of the series. There are attempts to analyze the growth rates of the terms involved, particularly comparing polynomial and exponential functions.

Discussion Status

The discussion is active, with participants offering various insights and questioning the validity of intuitive arguments regarding convergence. Some guidance on convergence tests has been suggested, but no consensus on a definitive approach has been reached.

Contextual Notes

Participants express a need for a mathematical proof of absolute convergence and discuss the implications of different convergence tests. There is an acknowledgment of the complexity of the series and the challenges in demonstrating convergence rigorously.

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The series, which is by all accounts nefarious, is (-1)^(n)*n*e^(-2^n).

In an attempt to subdue this monster, I made it into (-1)^(n)*n*/e^(2^n), but I do not want to wing the rest of the solution.

So, I ask for your help. Help me, brothers, like there is no tomorrow.
 
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Seems like a good candidate for Leibniz criterion of alternate series. If the general term in absolute value decrease and goes to zero, then the series converges.
 
BTW, troglodyte simply means underground dweller.
 
Thanks, but I need to know why it converges absolutely, which is the case...
 
Can't you think of a convergence test you could apply on n*e^(-2^n) ?
 
if tha absolute value converges...

n/e^(2n), I would assume e grows faster since it is an exponential function...so the abs value converges?
 
That's an intuitive argument, not a mathematical proof.

(And the argument is flawed too. For instance, for the series of 1/n. We have that 1/n-->0, but the series of 1/n still diverges.)
 
Last edited:
Ok, so how else can I show that it is abs convergent? How should I demonstrate this?
 
There is a plethora of citerion to determine the convergence of a series. Have you tried them all?
 
  • #10
The vocabulary in this thread ROCKS!

Casey
 

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