How Can I Estimate the Cutoff Voltage of a MOSFET From a Graph?

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Discussion Overview

The discussion revolves around estimating the cutoff voltage (threshold voltage) of MOSFETs from a graph of drain current (Ids) versus drain-source voltage (Vds) for various gate-source voltages (Vgs). Participants explore methods to derive this voltage from experimental data and graphs, focusing on the saturation region behavior of MOSFETs.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant suggests using the relationship I_d ∝ (V_{GS} - V_T)^2 in the saturation region to plot √(-Id) versus Vgs to find the threshold voltage (Vt).
  • Another participant estimates the threshold voltage to be about -6 volts based on the graph, stating that no current flows unless the gate voltage is at least -6 volts.
  • A different viewpoint argues that the threshold voltage is significantly less than -6 volts and recommends generating a specific graph to clarify this.
  • Some participants emphasize that the graph of drain current versus gate voltage would provide more useful information for estimating the cutoff voltage.
  • There is a contention regarding the accuracy of estimating the threshold voltage, with one participant asserting that a more precise value can be obtained from the graph without additional measurements.

Areas of Agreement / Disagreement

Participants express differing opinions on the threshold voltage estimation, with no consensus reached on the exact value or the best method to derive it from the provided graph. Multiple competing views remain regarding the interpretation of the data.

Contextual Notes

Participants note potential non-linearity in the turn-on behavior of the FET, which may affect the accuracy of the threshold voltage estimation. The discussion does not resolve the implications of this non-linearity.

Lith1um
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Hi,

I recently conducted a lab experiment involving several mosfets of varying channel length and width and have plotted Ids against Vds for different values of Vgs (below is one of the graphs).
15oe70l.png

I am now trying to find the threshold voltage of each mosfet using their graphs although I am having trouble figuring out how to do that and cannot find much help that is already online (I'm probably just bad at using google). Any help concerning this would be greatly appreciated.

Thanks,
Alex
 
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If you look up the equations for the current of a MOSFET, you will find that in the saturation region:
I_d \propto (V_{GS} - V_T)^2

So, I would choose a value of Vds where the device is in the saturation region (Vds = -7V or -8V looks good), and the plot √(-Id) vs Vgs. The intercept should give you Vt.
 
The threshold voltage is the voltage needed from gate to source to make the FET conduct current from drain to source.

You can estimate this from your graph. It is about -6 volts, because no current flows at any collector voltage unless the gate voltage is at least -6 volts.
 
The threshold voltage is significantly less (in magnitude) than 6V, which you will see if you make the graph I recommended.
 
The question asked was, using THAT graph, how would you estimate the cutoff voltage.

Given that the lowest value of gate voltage given is -7 volts, you could just say " something less than 7 volts".

There may be some non linearity in the turn-on behaviour of the FET but we don't know at this stage.

The graph of drain current vs gate voltage would be much more useful, as you suggest.
 
vk6kro said:
The question asked was, using THAT graph, how would you estimate the cutoff voltage.

Given that the lowest value of gate voltage given is -7 volts, you could just say " something less than 7 volts".

There may be some non linearity in the turn-on behaviour of the FET but we don't know at this stage.

The graph of drain current vs gate voltage would be much more useful, as you suggest.

You're not getting it. You can quantitatively extract the threshold voltage from the graph that the OP has by just generating the plot I suggested. No more measurements are required. This will give you a much more accurate value than "less than 7V".
 

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