- #1
How can I generate a triangle wave using an op-amp?
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Discussion Overview
The discussion revolves around generating a triangle wave using an operational amplifier (op-amp). Participants explore the underlying concepts, circuit design, and functionality of a triangle wave generator, including its components and operation.
Discussion Character
- Technical explanation
- Conceptual clarification
- Debate/contested
Main Points Raised
- One participant shares a schematic of a triple wave generator and seeks clarification on the concept of generating triangle waves.
- Another participant explains that integrating a square wave results in a triangle wave and mentions the role of diodes in setting the amplitude of the waveforms.
- A participant expresses confusion about the operation of the triangle wave generator and requests further explanation.
- An electronic engineer notes that feeding a capacitor with a current source leads to a linear ramp voltage, emphasizing the importance of the capacitor in the feedback path for maintaining constant voltage levels at the op-amp inputs.
Areas of Agreement / Disagreement
Participants present various viewpoints and explanations regarding the operation of the triangle wave generator, but there is no consensus on the complete understanding of the circuit or its components. Some participants provide technical insights while others seek clarification, indicating an ongoing exploration of the topic.
Contextual Notes
Some assumptions about input offset voltages and open loop gain effects are mentioned but not fully explored, leaving potential gaps in understanding the complete operation of the circuit.
- #2
berkeman
Admin
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It's an amplifying buffer for the input square wave, followed by the integrator. When you integrate a square wave, you get a triangle wave. The zener and other diode are used to set the amplitude of the square wave, and thus the amplitude of the tri wave.
- #3
- #4
Averagesupernova
Science Advisor
Gold Member
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Electronic engineer: Any time we feed a capacitor with a current source the capacitor develops a linear ramp voltage across it. Since the capacitor in your schematic is the ONLY component in the feedback path there will be a constant current through it if the inverting and non-inverting inputs are to remain the same voltage. Of course there is a bit more to it since we are not figuring input offset voltages, the offset due to open loop gain and things of this nature.
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