How can I prove the trig identity sinxcosxsec^2x = tanx?

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seastick
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1. How do I prove sinxcosxsec^2x=tanx



Homework Equations


sec^2x = tan^2x + 1


The Attempt at a Solution




sinxcosx(tan^2x + 1)
tan^2xsinxcosx +sinxcosx
sin^2x/cos^2x*sinxcosx + sinxcosx - is this valid?

I'm not sure what I've done is even correct - but it doesn't seem to be going anywhere helpful?

 
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Rewrite secant squared as 1/cos squared. The you'll have (sincos)/(coscos). Cancel cosines and you're done. I'll edit this from my computer and add arguments later!
 
secant = 1/cosine
cosecant = 1/sine
cotangent = 1/tangent
 
No, this is the one that's featured on the new US coins ;)