How can I solve the integral of 1/(1+x^4) from 0 to ∞?

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The integral of 1/(1+x^4) from 0 to ∞ can be approached using contour integration and the residue theorem, which are essential techniques in complex analysis. Several users attempted various methods including integration by parts and substitutions but found themselves unable to derive an analytical solution. A hint was provided to factor the expression x^4 + 1, but it was later deemed ineffective for this specific integral. Numerical integration was performed, but the focus remains on obtaining an analytical solution.

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∫1/(1+x^4) dx, from 0 to ∞


I have tried integration per partes, several different substitutions and transformation into different coordinate system but i have always only found another equivalent integral that i was not able to solve... I have also performed a numerical integration, but i need an analytical solution...
Thanks
 
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You should be able to work out the indefinite integral with one substitution. By the way, what is the derivative of the arc tangent?
 
vokurka said:
∫1/(1+x^4) dx, from 0 to ∞


I have tried integration per partes, several different substitutions and transformation into different coordinate system but i have always only found another equivalent integral that i was not able to solve... I have also performed a numerical integration, but i need an analytical solution...
Thanks

Partial fractions.
 
vokurka said:
∫1/(1+x^4) dx, from 0 to ∞ I have tried integration per partes, several different substitutions and transformation into different coordinate system but i have always only found another equivalent integral that i was not able to solve... I have also performed a numerical integration, but i need an analytical solution...
Thanks

Hint: ##x^4 + 1 = (x^2+1)^2 - (\sqrt{2}x)^2##. Rearrange, factorise.

Then use what Ray suggested.
 
Try substituting ##\sqrt{u}=x##.

Edit: Sorry, this doesn't actually work. Disregard!
 
Last edited:
You have a definite integral. I'd suggest using contour integration and the residue theorem if you know that technique.
 

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