How Can I Solve This Static Equilibrium Problem?

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Emanuel0406
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Handwritten page with the static equilibrium rules and a free body diagram of a beam with forces F1 to F4 at angles, F4 = 100 N at 0.5 m, and F2 cos 61 and F3 cos 53 components labelled.
Handwritten worked solution on paper: a) sum of forces on x axis equal zero, F3 sin 37 - F2 sin 61 = 0; b) sum of forces on y axis equal zero, F1 - 100 - F2 cos 61 - F3 cos 37 = 0; c) torque setup with a pivot point diagram showing a horizontal bar with F1 upward, 0.1 m and 0.6 m labels, and F4 = 100 N downward.
Handwritten torque calculation: F1 times 0.1 m minus 100 times 0.6 m equals 0, giving F1 = 600 N in a box, followed by the question Now where do I go from here? :(
Hello! I was wondering if anyone could give me a hand with the following problem. I am stuck and I don't know how to solve it. You can see attached the problem and my work so far. Thank you very much for your help.
Phone screenshot of a printed homework question on static equilibrium, showing a horizontal beam with forces F1, F2, F3 and F4 acting, F4 pointing down at the right end, and angle labels 45 and 30 degrees with 0.1 m and 0.6 m distances marked.
 
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  • Phone screenshot of a printed homework question on static equilibrium, showing a horizontal beam with forces F1, F2, F3 and F4 acting, F4 pointing down at the right end, and angle labels 45 and 30 degrees with 0.1 m and 0.6 m distances marked.
    Screenshot_2018-01-09-12-57-43.png
    6.8 KB · Views: 479
  • Handwritten notes on static equilibrium conditions, then a diagram of a horizontal beam with forces F1, F2, F3 and F4 = 100 N, and a free body diagram below with force components.
    20180110_195340_Night.jpg
    15.1 KB · Views: 586
  • Handwritten page with the static equilibrium rules and a free body diagram of a beam with forces F1 to F4 at angles, F4 = 100 N at 0.5 m, and F2 cos 61 and F3 cos 53 components labelled.
    20180110_195340_Night.jpg
    15.1 KB · Views: 757
  • Handwritten worked solution on paper: a) sum of forces on x axis equal zero, F3 sin 37 - F2 sin 61 = 0; b) sum of forces on y axis equal zero, F1 - 100 - F2 cos 61 - F3 cos 37 = 0; c) torque setup with a pivot point diagram showing a horizontal bar with F1 upward, 0.1 m and 0.6 m labels, and F4 = 100 N downward.
    20180110_195420_Night.jpg
    20.7 KB · Views: 761
  • Handwritten torque calculation: F1 times 0.1 m minus 100 times 0.6 m equals 0, giving F1 = 600 N in a box, followed by the question Now where do I go from here? :(
    20180110_195552_Night.jpg
    17.2 KB · Views: 754
You were already asked once in your other thread to please use better images (or just type your work into the forum window). These images are no better.

https://www.physicsforums.com/threads/static-equilibrium.936574/

Do you have access to a printer/scanner? When you have better images or take the time to type your work into the forum, please re-post a new thread, and be sure to use the Homework Help Template you are provided. Thank you.