- #1
Anil Radhakrishnan
- 3
- 0
Equations: Net torque=0=Net force
I believe this is a static equilibrium question but can't figure out how to do it
Static Equilibrium Problem involving Moments
- Thread starter Anil Radhakrishnan
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Homework Help Overview
The discussion revolves around a static equilibrium problem involving moments, where participants are analyzing forces and torques acting on a system. The original poster expresses uncertainty in applying the principles of static equilibrium to solve the problem.
Discussion Character
- Exploratory, Assumption checking, Problem interpretation
Approaches and Questions Raised
- Participants discuss the necessity for net force and net torque to be zero, suggesting equations based on these conditions. There are attempts to split forces and analyze their components, but some participants express difficulty in achieving balance.
Discussion Status
The conversation is ongoing, with participants providing guidance on how to approach the problem by focusing on the correct axes and forces involved. There is recognition of the need to clarify the roles of different forces, but no consensus has been reached on a solution.
Contextual Notes
Participants note the importance of distinguishing between forces along the axes and those along the rod, indicating potential confusion in the setup of the problem. The weights of the rod and an additional mass are mentioned, along with components of forces acting at specific points.
Equations: Net torque=0=Net force
I believe this is a static equilibrium question but can't figure out how to do it
- #2
Delta2
Homework Helper
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The net force on the x-axis must be zero. What equation can you make from this fact?
Also the net torque is zero. Take the torques around the A point. What equation can you make?
Solving these two equations with two unknowns (F_x and the force from cable ) will get you the result.
Also the net torque is zero. Take the torques around the A point. What equation can you make?
Solving these two equations with two unknowns (F_x and the force from cable ) will get you the result.
- #3
Anil Radhakrishnan
- 3
- 0
this is what i have split the forces as till now,
somehow i can't get them to cancel
- #4
Delta2
Homework Helper
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You get involved with the forces along the line of the 80Kg rod, that's not what you should do, the x-axis is not the line of the 80Kg rod, the first picture at OP shows which are the x -axis and the y-axis.
In the y-axis you got the weights of the rod and the mass m, 80Kg and 10Kg respectively (and the F_y component of the force from wall at A).
In the x-axis you got F_x and the tension T from the cable.
In the y-axis you got the weights of the rod and the mass m, 80Kg and 10Kg respectively (and the F_y component of the force from wall at A).
In the x-axis you got F_x and the tension T from the cable.
- #5
Anil Radhakrishnan
- 3
- 0
ah got it thank youDelta² said:
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