How can I solve this without using Reduction Formula?

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To solve the integral of cot^2 x / csc^8 x dx without using the reduction formula, first convert the integrand to sine and cosine functions. The expression can be rewritten as f(x) = cos^2(x) sin^6(x). By applying the identity cos^2(x) = 1 - sin^2(x), the integral can be expressed in terms of integrals of sine functions, specifically I_n = ∫sin^n(x) dx. Integration by parts can then be used to relate I_n to I_{n-2}, allowing for a systematic approach to solve the integral. This method avoids the lengthy reduction formula while still leading to the desired solution.
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Homework Statement


integral of cot^2 x / csc^8 x dx

Homework Equations


u = cot x
du = csc^2 x du

The Attempt at a Solution


if I use reduction formula I could answer this but it's going to be very very LONG SOLUTION

I just need some basic integral work.
 
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First convert the expression to only sin and cos and then think of proper substitution. If youdo not wish to use reduction formula you need to juggle up the expressions and remove powers to get expression in terms of multiple angles.
 
Let'sthink said:
First convert the expression to only sin and cos and then think of proper substitution. If youdo not wish to use reduction formula you need to juggle up the expressions and remove powers to get expression in terms of multiple angles.
Dj Pedobear said:

Homework Statement


integral of cot^2 x / csc^8 x dx

Homework Equations


u = cot x
du = csc^2 x du

The Attempt at a Solution


if I use reduction formula I could answer this but it's going to be very very LONG SOLUTION

I just need some basic integral work.

Write the integrand as ##f(x) = \cos^2(x) \sin^6 (x)##. Use ##\cos^2(x) = 1 -\sin^2(x)## to get your integral ##F = \int f(x) \, dx## in the form ##F = I_6-I_8##, where ##I_n = \int \sin^n(x) \, dx##.

Apply integration by parts to ##I_n##, using ##u = \sin^{n-1}(x)## and ##dv = \sin(x) \, dx##. This gives
I_n = -\cos(x) \sin^{n-1}(x) + (n-1) \int \cos^2(x) \sin^{n-2}(x) \, dx = -\cos(x) \sin^{n-1}(x) + (n-1) [I_{n-2} - I_n]
This is an equation connecting ##I_n## to ##I_{n-2}##, so you can solve it to express ##I_n## in terms of ##\sin(x), \cos(x)## and ##I_{n-2}##. Finally, you can express ##I_8## in terms of ##I_6##, then ##I_6## in terms of ##I_4##, etc. The answer you want will drop out pretty quickly and easily.
 
thx :D
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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