Integrating cot^4 x (csc^4 x) dx Using Identities and U Substitution

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SUMMARY

The integral ∫(cot^4 x)(csc^4 x) dx can be approached using trigonometric identities and u-substitution. The discussion highlights the transformation of the integral into ∫cot^4 x (cot^2 x + 1)^2 dx, leading to ∫cot^8 x + 2cot^6 x + cot^4 x dx. Participants emphasized the importance of recognizing the derivative of cot(x) to facilitate the integration process.

PREREQUISITES
  • Understanding of trigonometric identities, specifically cotangent and cosecant functions.
  • Familiarity with u-substitution in integral calculus.
  • Knowledge of integration techniques for polynomial expressions.
  • Ability to differentiate trigonometric functions, particularly cotangent.
NEXT STEPS
  • Study the application of trigonometric identities in integration.
  • Learn advanced u-substitution techniques for complex integrals.
  • Explore reduction formulas for integrals involving trigonometric functions.
  • Review the derivatives of trigonometric functions to enhance integration skills.
USEFUL FOR

Students and educators in calculus, mathematicians focusing on integral calculus, and anyone seeking to improve their skills in integrating trigonometric functions using identities and substitution methods.

johnhuntsman
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∫(cot^4 x) (csc^4 x) dx

Wolfram wants to use the reduction formula, but I'm meant to do this just using identities and u substitution. I was thinking something along the lines of:

=∫cot^4 x (cot^2 x + 1)^2 dx

=∫cot^8 x + 2cot^6 x + cot^4 x dx

but I don't know where to go from there.
 
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Try ∫(cot^4 x) (1+cot^2 x) (csc^2 x) dx

Whats the derivative of cot(x)?
 
Thanks. Worked it out with that in mind. I appreciate it : D
 

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