How can integration by parts be used to solve this integral?

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SUMMARY

The integral of x^2ln(x)dx can be solved using integration by parts, where u = ln(x) and dv = x^2dx. The resulting expression is ∫ x^2 ln(x)dx = (x^3/3)ln(x) - (1/3)∫ x^3/x dx + C. The solution requires careful simplification of the integrand and attention to the constant of integration. This method effectively utilizes the properties of logarithmic functions in calculus.

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Homework Statement



integral of x^2ln(x)dx

Homework Equations





The Attempt at a Solution



u=ln(x)
du= 1/x
dv=x2dx
x^3/3

integral x^2ln(x)dx = ln(x)x^3/3-intergral(x^3/3)(1/x)
 
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jpd5184 said:

Homework Statement



integral of x^2ln(x)dx

Homework Equations





The Attempt at a Solution



u=ln(x)
du= 1/x
dv=x2dx
x^3/3

integral x^2ln(x)dx = ln(x)x^3/3-intergral(x^3/3)(1/x)
You're on the right path. Just continue what you're doing, but simplify the integrand on the right. Don't forget dx or the constant of integration, though.

Here's the work in LaTeX. Click the equation to see what I did.
[tex]\int x^2 ln(x)dx = \frac{x^3}{3}ln(x) - \frac{1}{3}\int \frac{x^3}{x} dx + C[/tex]
 
The natural logarithm is also a function recognized by LaTeX. It has the code [itex]\ln x[/itex]. Its inverse, the exponential function in the base e also has a code [itex]\exp x[/itex].
 

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