How Can the Integral of 1/sqrt(x^2 - 1) Be Expressed Using Ln?

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SUMMARY

The integral of the function 1/sqrt(x^2 - 1) can be expressed as arccosh(x), which can be proven using logarithmic functions. Specifically, the integral can be rewritten in the form of Ln(x + sqrt(x^2 - 1)). The discussion emphasizes the use of trigonometric substitution, particularly x = sec(theta), to simplify the integral. This method effectively demonstrates the relationship between hyperbolic functions and logarithmic expressions.

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Homework Statement



\intdx/\sqrt{}x^2 -1
I actually know that the answer is arccosh(x) but I want to prove it in form of Ln(x+\sqrt{}x^2 -1)

Homework Equations


The Attempt at a Solution


I have tried many times such as u=x2-1 and u=x2
 
Last edited:
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Did you mean ...

\int\frac{dx}{\sqrt{x^2-1}}
 


Yes I mean

LaTeX Code: \\int\\frac{dx}{\\sqrt{x^2-1}}
 


Use a trigo substitution here.
 


Thank you now I got it x=sect
 

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