How can the length of a normal vector matter?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 1K views
ainster31
Messages
158
Reaction score
1

Homework Statement



qIHY9.png


Homework Equations





The Attempt at a Solution



Solution:

zMjwn.png


Graph:

kYSoJ.png


For part a, I understand mathematically why the value of c matters. What I don't understand is how it can possibly matter intuitively.

I get that ##\overrightarrow { \nabla } F(x_{ 0 },y_{ 0 },z_{ 0 })=(0,c,0)## and therefore, c can't be any value. My question is: how can a tangent plane possibly depend on the length of the normal vector? If the vector is normal, then the length shouldn't matter because the vector will always be normal for all values for c except 0.
 
Physics news on Phys.org
You need two pieces of information to specify the plane: the normal and a point on the plane. ##c## goes into figuring out what point the plane passes through.
 
vela said:
You need two pieces of information to specify the plane: the normal and a point on the plane. ##c## goes into figuring out what point the plane passes through.

What are the effects on a tangent plane when you scale up and down ∇F but keep ∇F in the same direction?
 
##\nabla F## is determined by F, so you don't have the freedom to arbitrarily rescale it. If you mean what happens if you say, for example, ##\nabla F = (0, c/2, 0)## instead of ##\nabla F = (0, c, 0)##, why don't you try it and see what happens?